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anonymous
 one year ago
what is the simplest form of this expression
4(5y+4)+(7)(3y+1)
anonymous
 one year ago
what is the simplest form of this expression 4(5y+4)+(7)(3y+1)

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Owlcoffee
 one year ago
Best ResponseYou've already chosen the best response.1Apply the distributive property and operate similar terms, that'd give you the answer.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0need more help then that

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0distribute parentheses by outside terms (as owl suggested )

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0here is an example \[\huge\rm \color{red}{a}(b+c)=\color{red}{a} \times b + \color{red}{a} \times c =\color{reD}{a}b+\color{reD}{a}c\]

Owlcoffee
 one year ago
Best ResponseYou've already chosen the best response.1Just to extend Nneshas suggestion: \[(4)(5y)+(4)(4)+(7)(3y)+(7)(1)\]

Owlcoffee
 one year ago
Best ResponseYou've already chosen the best response.1Good, now, operate the terms that do and do not have "y" on their right side.

Owlcoffee
 one year ago
Best ResponseYou've already chosen the best response.1It will look like this: \[(20+21)y +(167)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay and can you just show me how to solve this step by step like in one of those pics things so i can fully understand this

Owlcoffee
 one year ago
Best ResponseYou've already chosen the best response.1Starting out with: \[4(5y+4)+(7)(3y+1)\] Whenever you want to simplify any mathematical expression you first get rid of what is called "groupings", which in this case is the parenthesis, so in order to do that, you always apply Distributive property: \(a(b+c)=ab+ac\) So, applying distributive property on the first and second parenthesis with their corresponding "outside term": \[20y+16+21y7\] This is a much simpler way of viewing the first mathematical expression but not the simplest, so in order to simplify it more, we will get rid of operations, those being addition and sustraction as you can see. The only way to do that is to reduce the terms of the mathematical expression, you might as well know that a "term" in mathematics is any number, variable or both, separated by a basic operation, that being "+" or "". And we can reduce terms if we can see that the only variable present is "y" and there are more than one term with a "y" on them, so we will take "common factor" (Which is the reverse of distributive) "y" on the terms that has it: \[(20+21)y+167\] That is also called "grouping like terms". now it's just a matter of arithmetics, which I will suppose you already know: \[(1)y+9\] Or better written as: \[y+9\]
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