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anonymous

  • one year ago

Graph of function f of x equals 2 to the power of negative x. Graph of function g of x equals 5 to the power of x. Graph of p of x is a line segment connecting points negative 1, negative 3 and 2, 12. Which function has all real numbers as its domain? Only f(x) Both g(x) and p(x) Both f(x) and g(x) Only p(x)

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    @ali2x2

  3. anonymous
    • one year ago
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    @henrry123

  4. anonymous
    • one year ago
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    will give medal for right answer

  5. geerky42
    • one year ago
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    What do you think? Can you plug -2 in p(x)?

  6. anonymous
    • one year ago
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    yeah u can ? i think

  7. geerky42
    • one year ago
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    ok what is p(-2)?

  8. anonymous
    • one year ago
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    -2p

  9. geerky42
    • one year ago
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    Domain is basically "group" of x-coordinates. Do p(x) have value in x=-2 ?

  10. geerky42
    • one year ago
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    p(x) is function, not variable

  11. anonymous
    • one year ago
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    i am like very bad at math lol but i think it dont

  12. geerky42
    • one year ago
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    let's just say you have h(x) = x h(x) has domain of all real number because you can plug any values in h(x)

  13. anonymous
    • one year ago
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    okay

  14. geerky42
    • one year ago
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    You can see that p(x) only goes from about -1 to 2 in x-coordinate, right?

  15. anonymous
    • one year ago
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    yes i do

  16. geerky42
    • one year ago
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    |dw:1438987265095:dw|

  17. anonymous
    • one year ago
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    |dw:1438987281477:dw|

  18. geerky42
    • one year ago
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    yeah there are ends. So domain of p(x) is not all real number. Does that make sense?

  19. anonymous
    • one year ago
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    yes it do

  20. geerky42
    • one year ago
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    p(-3) is not definied (has no value) because -3 is not in domain of p(x)

  21. geerky42
    • one year ago
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    okay what about f(x) and g(x)?

  22. geerky42
    • one year ago
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    defined *

  23. anonymous
    • one year ago
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    |dw:1438987402176:dw|

  24. geerky42
    • one year ago
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    \(f(x) = 2^{-x}\) \(g(x)=5^x\) Is there any x value you cannot plug in?

  25. anonymous
    • one year ago
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    -2

  26. anonymous
    • one year ago
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    and 1 ?

  27. geerky42
    • one year ago
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    f(-2) has no value?

  28. geerky42
    • one year ago
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    well f(-2) = \(2^{-(-2)} = 2^2 = 4\) So -2 is in domain of f(x). same goes for g(x)

  29. anonymous
    • one year ago
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    okay i was right with the -2

  30. geerky42
    • one year ago
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    well domain is more than just -2.

  31. geerky42
    • one year ago
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    does f(10) have value? f(100)? f(1000)?

  32. anonymous
    • one year ago
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    100

  33. geerky42
    • one year ago
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    and not f(10) nor f(1000)?

  34. geerky42
    • one year ago
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    Looks like you don't understand how functions work.

  35. anonymous
    • one year ago
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    i dont

  36. geerky42
    • one year ago
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    you can think of it as "machine"|dw:1438987847196:dw| like f(x) would "change" -2 to any number, depend on what f(x) is. Make sense so far?

  37. anonymous
    • one year ago
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    okay i see what u mean

  38. geerky42
    • one year ago
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    domain is basically like what number you can put into machine

  39. geerky42
    • one year ago
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    if domain is 1 to 3, you can only put in any number between 1 to 3. No 5 or something

  40. geerky42
    • one year ago
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    If domain is real number, that means you can put in ANY (real) number.

  41. anonymous
    • one year ago
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    okay

  42. geerky42
    • one year ago
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    do you understand?

  43. anonymous
    • one year ago
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    so i can say any number

  44. geerky42
    • one year ago
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    well, can you plug any number in f(x) and g(x)? That's the question

  45. anonymous
    • one year ago
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    yes u can

  46. geerky42
    • one year ago
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    ok so domain of f(x) and g(x) is real number.

  47. anonymous
    • one year ago
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    yes

  48. geerky42
    • one year ago
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    So answer is C.

  49. geerky42
    • one year ago
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    sorry for taking so long time lol

  50. anonymous
    • one year ago
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    thxs for trying to show me i really do want to learn math

  51. geerky42
    • one year ago
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    Glad to hear that!

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