anonymous
  • anonymous
Graph of function f of x equals 2 to the power of negative x. Graph of function g of x equals 5 to the power of x. Graph of p of x is a line segment connecting points negative 1, negative 3 and 2, 12. Which function has all real numbers as its domain? Only f(x) Both g(x) and p(x) Both f(x) and g(x) Only p(x)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
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anonymous
  • anonymous
@ali2x2
anonymous
  • anonymous
@henrry123

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More answers

anonymous
  • anonymous
will give medal for right answer
geerky42
  • geerky42
What do you think? Can you plug -2 in p(x)?
anonymous
  • anonymous
yeah u can ? i think
geerky42
  • geerky42
ok what is p(-2)?
anonymous
  • anonymous
-2p
geerky42
  • geerky42
Domain is basically "group" of x-coordinates. Do p(x) have value in x=-2 ?
geerky42
  • geerky42
p(x) is function, not variable
anonymous
  • anonymous
i am like very bad at math lol but i think it dont
geerky42
  • geerky42
let's just say you have h(x) = x h(x) has domain of all real number because you can plug any values in h(x)
anonymous
  • anonymous
okay
geerky42
  • geerky42
You can see that p(x) only goes from about -1 to 2 in x-coordinate, right?
anonymous
  • anonymous
yes i do
geerky42
  • geerky42
|dw:1438987265095:dw|
anonymous
  • anonymous
|dw:1438987281477:dw|
geerky42
  • geerky42
yeah there are ends. So domain of p(x) is not all real number. Does that make sense?
anonymous
  • anonymous
yes it do
geerky42
  • geerky42
p(-3) is not definied (has no value) because -3 is not in domain of p(x)
geerky42
  • geerky42
okay what about f(x) and g(x)?
geerky42
  • geerky42
defined *
anonymous
  • anonymous
|dw:1438987402176:dw|
geerky42
  • geerky42
\(f(x) = 2^{-x}\) \(g(x)=5^x\) Is there any x value you cannot plug in?
anonymous
  • anonymous
-2
anonymous
  • anonymous
and 1 ?
geerky42
  • geerky42
f(-2) has no value?
geerky42
  • geerky42
well f(-2) = \(2^{-(-2)} = 2^2 = 4\) So -2 is in domain of f(x). same goes for g(x)
anonymous
  • anonymous
okay i was right with the -2
geerky42
  • geerky42
well domain is more than just -2.
geerky42
  • geerky42
does f(10) have value? f(100)? f(1000)?
anonymous
  • anonymous
100
geerky42
  • geerky42
and not f(10) nor f(1000)?
geerky42
  • geerky42
Looks like you don't understand how functions work.
anonymous
  • anonymous
i dont
geerky42
  • geerky42
you can think of it as "machine"|dw:1438987847196:dw| like f(x) would "change" -2 to any number, depend on what f(x) is. Make sense so far?
anonymous
  • anonymous
okay i see what u mean
geerky42
  • geerky42
domain is basically like what number you can put into machine
geerky42
  • geerky42
if domain is 1 to 3, you can only put in any number between 1 to 3. No 5 or something
geerky42
  • geerky42
If domain is real number, that means you can put in ANY (real) number.
anonymous
  • anonymous
okay
geerky42
  • geerky42
do you understand?
anonymous
  • anonymous
so i can say any number
geerky42
  • geerky42
well, can you plug any number in f(x) and g(x)? That's the question
anonymous
  • anonymous
yes u can
geerky42
  • geerky42
ok so domain of f(x) and g(x) is real number.
anonymous
  • anonymous
yes
geerky42
  • geerky42
So answer is C.
geerky42
  • geerky42
sorry for taking so long time lol
anonymous
  • anonymous
thxs for trying to show me i really do want to learn math
geerky42
  • geerky42
Glad to hear that!

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