## anonymous one year ago BUM BUM BUMMMMMMM I NEED HELPPPPPP!!!! The figure shows the graph of the equation y =k–x2, where k is a constant. If the area of triangle ABC is 1/8, what is the value of k?

1. anonymous

|dw:1438987265534:dw|

2. anonymous

can i help

3. wintersuntime

I got 1/4, by taking the area of triangle 1/2xbasexheight=1/8. basexheight will be 1/4. Hence, k = 1/4

4. wintersuntime

Do you need any more help ?

5. Loser66

@wintersuntime base x height = 1/4, how can you know k =1/4? I agree that k =1/4 but don't understand your logic.

6. wintersuntime

I'll be right back it's cuz im helping someone else

7. dumbcow

|dw:1438997626829:dw| $A = \frac{1}{2}(2 \sqrt{k})(k) = \frac{1}{8}$ $k^{3/2} = \frac{1}{8}$ $k = \frac{1}{8^{2/3}} = \frac{1}{(\sqrt[3]{8})^2} = \frac{1}{4}$

8. triciaal

when x = 0 y = k