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Mahent1

  • one year ago

radical addition

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  1. Mahent1
    • one year ago
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    \[\sqrt[3]{20}+\sqrt[2]{5}\]

  2. Mahent1
    • one year ago
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    @geerky42 @kropot72

  3. Mahent1
    • one year ago
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    not even a single person is helping

  4. Mahent1
    • one year ago
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    @YanaSidlinskiy @Kainui @kropot72 @Hero @campbell_st @iambatman @freckles @ganeshie8

  5. Mahent1
    • one year ago
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    @Nnesha are you going to help or just stare at the question?

  6. YanaSidlinskiy
    • one year ago
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    Rule #1: Be nice:)

  7. Nnesha
    • one year ago
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    \(\color{blue}{\text{Originally Posted by}}\) @Mahent1 \[\sqrt[3]{20}+\sqrt[2]{5}\] \(\color{blue}{\text{End of Quote}}\) first of all are you sure its square root of 5 ? \[\sqrt{ } \] simple radical sign means square root no need to write 2

  8. Mahent1
    • one year ago
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    i copied it from the question

  9. YanaSidlinskiy
    • one year ago
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    Have you tried attempting the problem? If so, what was your answer?

  10. Nnesha
    • one year ago
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    |dw:1438988429502:dw| :=)

  11. geerky42
    • one year ago
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    Exactly what's the question here? Looks like you cannot simplify any further.

  12. Nnesha
    • one year ago
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    take a screenshot. o^_^o

  13. Mahent1
    • one year ago
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    i need it in simplest form

  14. geerky42
    • one year ago
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    Like you want \(\sqrt[3]{20}+\sqrt5\) in decimal form?

  15. geerky42
    • one year ago
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    because you can't really simplify it.

  16. Mahent1
    • one year ago
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    here's what it says: What is \[3\sqrt{20}+2\sqrt{5}\] in simplest form A 5√5 B 5√25 C 14√5 D 8√5

  17. Nnesha
    • one year ago
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    o^_^o ^

  18. geerky42
    • one year ago
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    well, this clears things up

  19. Nnesha
    • one year ago
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    what are the factors of 20 ?

  20. Mahent1
    • one year ago
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    1, 2 , 4, 5 ,10, 20 ?

  21. YanaSidlinskiy
    • one year ago
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    As to what Nnesha has said, it does simplify.

  22. geerky42
    • one year ago
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    OP initially typed \(\sqrt[3]{20}+\sqrt5\), which cannot be simplified.

  23. Nnesha
    • one year ago
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    alright one of the number should be perfect square so 4,5 looks good :=) \[\huge\rm 2 \sqrt{\color{reD}{4} \times 5} + \sqrt{5}\] 1st) take square root of 4 which is = 2 \[\huge\rm 2 \times \color{reD}{2} \sqrt{ 5} + \sqrt{5}\] multiply the numbers front of the sqrt{5} and then take out the commmon factor

  24. Mahent1
    • one year ago
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    4?

  25. Nnesha
    • one year ago
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    \[\huge\rm 4 \sqrt{5} + \sqrt{5}\] what is common factor ?

  26. Mahent1
    • one year ago
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    √5?

  27. Nnesha
    • one year ago
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    yes right so take it out \[\sqrt{5}(???)\] when you take out sqrt{5{ from 4sqrt{5} what would u have lef?

  28. Mahent1
    • one year ago
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    4

  29. Nnesha
    • one year ago
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    yes right so when you take out sqrt{5} from sqr{5} what would have left?

  30. Mahent1
    • one year ago
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    nothing?

  31. Nnesha
    • one year ago
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    |dw:1438989226123:dw|

  32. Nnesha
    • one year ago
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    nothing is not an answer :=) bascally you need to divide both terms by common factor \[\frac{ 4\sqrt{5} }{ \sqrt{5} } + \frac{ \sqrt{5} }{ \sqrt{5} }\] \[\sqrt{5}(4+???)\] sqrt{5} divide by square root 5 ??

  33. Mahent1
    • one year ago
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    1

  34. Nnesha
    • one year ago
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    yes right so nothing is not an answer :=) \[\sqrt{5}(4+1)\] = ??

  35. Mahent1
    • one year ago
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    4+1=5

  36. Nnesha
    • one year ago
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    yes right so final answer is ?

  37. Mahent1
    • one year ago
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    5√5?

  38. Nnesha
    • one year ago
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    :=)

  39. Nnesha
    • one year ago
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    that's right! :=)

  40. Mahent1
    • one year ago
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    ok thanks...

  41. Nnesha
    • one year ago
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    my pleasure :=)

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