- anonymous

The graph below shows the relationship between the number of months different students practiced baseball and the number of games they won:
Part A: What is the approximate y-intercept of the line of best fit and what does it represent? (5 points)
Part B: Write the equation for the line of best fit in slope-intercept form and use it to predict the number of games that could be won after 13 months of practice. (5 points)

- schrodinger

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- anonymous

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- anonymous

any help would be appreciated

- anonymous

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## More answers

- jim_thompson5910

do you see what the y-intercept is?

- anonymous

well i know that the y-intercept is the place where a line crosses the y-axis

- jim_thompson5910

which is where in this case?

- anonymous

is it the second dot ? ike 0,1?

- jim_thompson5910

focus on the line and not the dot. The dot is a bit below the line

- jim_thompson5910

So it's probably around (0,1.5) maybe

- anonymous

so what do i do?

- jim_thompson5910

do you agree that the y-intercept is around (0,1.5) ?

- anonymous

well i said 1 so why is it 1.5?

- jim_thompson5910

I zoomed in and saw that the point at (0,1) is slightly below the place where the line crosses the y axis

- jim_thompson5910

|dw:1438992422113:dw|

- jim_thompson5910

|dw:1438992436303:dw|

- jim_thompson5910

|dw:1438992467887:dw|

- anonymous

oh alright i see now

- jim_thompson5910

what does it represent?

- anonymous

the numbers of games they won?

- anonymous

is that what it means

- jim_thompson5910

what is the line of best fit trying to do?

- anonymous

i dont know ...

- jim_thompson5910

we have a bunch of points and the line of best fit is trying to get as close as possible to each point, right?

- anonymous

yeah

- jim_thompson5910

the line of best fit is a tool used to predict y scores based on given x values
if we know the number of months practiced, then we can use it to predict the number of games one based on the regression line

- jim_thompson5910

what is the x value at the y-intercept?

- anonymous

0

- jim_thompson5910

when the number of months of practice is 0, the predicted number of games won would be around 1.5
that's what the y-intercept tells us

- anonymous

thanks i know ive been hard work haha could you help me with the other part

- jim_thompson5910

you'll first need to write down all of the points shown on the graph
make one big list of points

- anonymous

alright

- jim_thompson5910

once you have your list, paste it into
http://www.alcula.com/calculators/statistics/linear-regression/
to calculate the regression line

- anonymous

this will give me the equation?

- anonymous

ok i filled it in

- jim_thompson5910

yeah it should be calculated/shown after you hit the "submit data" button

- anonymous

it just shows the graph ?

- jim_thompson5910

I think the equation is shown above the graph

- jim_thompson5910

above where it says "Regression line equation:"

- anonymous

/.Sample size: 10
Mean x (x̄): 4.8
Mean y (ȳ): 10.85
Intercept (a): 1.9772727272727
Slope (b): 1.8484848484848
Regression line equation: y=1.9772727272727+1.8484848484848x

- jim_thompson5910

so y=1.9772727272727+1.8484848484848x

- anonymous

thats the equation ?

- jim_thompson5910

I was pretty close. 1.97 is close to 1.5
well closer to 2 actually

- jim_thompson5910

yeah

- anonymous

so do i change part a to 1.97

- jim_thompson5910

no that was an estimate based on just looking at the graph

- jim_thompson5910

it doesn't have to be perfect

- anonymous

oh alright thanks bunches

- jim_thompson5910

no problem

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