anonymous
  • anonymous
If f[x] = Integrate]t/0 4 Sin[x^3] what does it mean to 'give a clean formula' for f'[x] ? latex coming ...
Mathematics
  • Stacey Warren - Expert brainly.com
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katieb
  • katieb
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anonymous
  • anonymous
\[f(x)= \int\limits_{0}^{t} 4 \sin (x^3) dx\]
Astrophysics
  • Astrophysics
Looks like they want you to use fundamental theorem of calculus part 1
anonymous
  • anonymous
would that not just be \[\int\limits_{0}^{t} f'(x) = f(t) - f(0)\] and there for f'(x) = 4 sin (x^3) Or is there more to it than that?

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Astrophysics
  • Astrophysics
Kind of all you have to do here is plug in t where x is
anonymous
  • anonymous
ahhh thats what I did wrong
anonymous
  • anonymous
thnx
Astrophysics
  • Astrophysics
So we have \[\int\limits_{0}^{t} 4 \sin(x^3) dx = 4\sin(t^4)=f'(x)\]eas right
Astrophysics
  • Astrophysics
easy*
Astrophysics
  • Astrophysics
Np :-)
anonymous
  • anonymous
had something like d/dx f[t] = f'[x]
Astrophysics
  • Astrophysics
Sort of haha, basically taking the derivative of integral, which just cancels out the integral, if that makes sense
Astrophysics
  • Astrophysics
It'll be rare for you to see fundamental theorem of calc part 1 after calc 1 xD
Astrophysics
  • Astrophysics
But part 2 what you did first is everywhere

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