A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
Please help me I will give you metals
anonymous
 one year ago
Please help me I will give you metals

This Question is Closed

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1were you able to find dy/dx ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes, I have the prime derivative I got 3x/y

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1correct \[\Large \frac{dy}{dx} = \frac{3x}{y}\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1Now apply the derivative to both sides \[\Large \frac{dy}{dx} = \frac{3x}{y}\] \[\Large \frac{d}{dx}\left[\frac{dy}{dx}\right] = \frac{d}{dx}\left[\frac{3x}{y}\right]\] \[\Large \frac{d^2y}{dx^2} = ??\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and then for the y'' i got 3yy'(3x)  4y^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and then I plug 3x/y on the y' right?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1correct and simplify

anonymous
 one year ago
Best ResponseYou've already chosen the best response.03y+(9x/y)  4y^2

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1I'm not getting the same thing

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@jim_thompson5910 , from this pint do I just plug the values of x and Y?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438995573413:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1\[\Large \frac{d^2y}{dx^2} = \frac{3y(3x)\frac{dy}{dx}}{y^2}\] \[\Large \frac{d^2y}{dx^2} = \frac{3y+3x\left(\frac{3x}{y}\right)}{y^2}\] \[\Large \frac{d^2y}{dx^2} = \frac{3y\frac{9x^2}{y}}{y^2}\] \[\Large \frac{d^2y}{dx^2} = \frac{3y{\color{red}{*y}}\frac{9x^2}{y}{\color{red}{*y}}}{y^2{\color{red}{*y}}}\] \[\Large \frac{d^2y}{dx^2} = \frac{3y{\color{red}{*y}}\frac{9x^2}{\cancel{y}}{\color{red}{*\cancel{y}}}}{y^2{\color{red}{*y}}}\] \[\Large \frac{d^2y}{dx^2} = \frac{3y^29x^2}{y^3}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh I see you simplified it, and from here. Do I plug the x and y values into this derivate?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1yeah, 21/8 = 2.625

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay, if they say that I need to put my answer into 2 decimal places, do i put 2.63?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay, thank you so much
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.