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anonymous

  • one year ago

find f'(-3), if f(x)=(2x^2-7x)(-x^2-7). round your answer to the nearest integer

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  1. Loser66
    • one year ago
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    just expand f(x) take derivative replace x =-3 in its derivative Done

  2. anonymous
    • one year ago
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    ok but I end up with a really bigggggggggg number

  3. Loser66
    • one year ago
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    Show your work, please

  4. anonymous
    • one year ago
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    ok here: f(-3)=(2(-3)^2-7(-3))(-(-3)^2)) f(-3)=-624 I know I did something wrong

  5. Loser66
    • one year ago
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    hey, your question is to find \(f'(-3)\) not \(f(-3)\)

  6. Loser66
    • one year ago
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    \(f(x) = (2x^2-7x)(-x^2-7)\) Use FOIL to expand it, what do you have?

  7. anonymous
    • one year ago
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    -2x^4+49x

  8. Loser66
    • one year ago
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    Nope |dw:1438996954403:dw|

  9. Loser66
    • one year ago
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    |dw:1438997014846:dw|

  10. Loser66
    • one year ago
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    Now, take derivative one by one, what do you get?

  11. anonymous
    • one year ago
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    a 2.

  12. Loser66
    • one year ago
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    I try to help but I need you help yourself also. I don't understand your comment.

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