## anonymous one year ago A rocket is fired straight up from a 60 ft. platform with an initial velocity of 96 ft/sec. The heigh of the rocket, h(t), is found using the function h\left( t \right) = - 16{t^2} + 96t + 60 where t is the time in seconds. Find the number of seconds required to reach the maximum height.

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1. IrishBoy123

hint, at max height, $$\large v(t)$$ = 0 and $$\large v(t) = \dot h(t) = \frac{dh}{dt}$$

2. IrishBoy123

or if that makes no sense to you, complete the square to find t at the peak of the parabola