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anonymous

  • one year ago

Celina measured the height of a window frame as 5.55 feet, but the actual height was 6 feet. What is the percentage of error in Celina's measurement? 6.45% 7.50% 9.12% 13.33%

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  1. jim_thompson5910
    • one year ago
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    https://www.mathsisfun.com/numbers/percentage-error.html \[\large \text{percent error} = \frac{| \text{approximate value}-\text{exact value}|}{|\text{exact value}|} \ \times 100\%\]

  2. anonymous
    • one year ago
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    5.55 - 6/6 x 100?

  3. jim_thompson5910
    • one year ago
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    I think you meant to say \[\Large \text{percent error} = \frac{| 5.55-6|}{|6|} \times 100\%\] right?

  4. anonymous
    • one year ago
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    i got -94.45...

  5. jim_thompson5910
    • one year ago
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    what is 5.55 - 6 equal to?

  6. anonymous
    • one year ago
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    -0.45

  7. jim_thompson5910
    • one year ago
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    |-0.45| = 0.45

  8. jim_thompson5910
    • one year ago
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    divide that by 6 then multiply by 100 to convert to a percentage

  9. anonymous
    • one year ago
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    is it b?

  10. jim_thompson5910
    • one year ago
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    yes

  11. anonymous
    • one year ago
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    i got 7.50

  12. jim_thompson5910
    • one year ago
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    me too

  13. anonymous
    • one year ago
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    ok thank you :)

  14. jim_thompson5910
    • one year ago
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    7.50%

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