## anonymous one year ago Celina measured the height of a window frame as 5.55 feet, but the actual height was 6 feet. What is the percentage of error in Celina's measurement? 6.45% 7.50% 9.12% 13.33%

1. jim_thompson5910

https://www.mathsisfun.com/numbers/percentage-error.html $\large \text{percent error} = \frac{| \text{approximate value}-\text{exact value}|}{|\text{exact value}|} \ \times 100\%$

2. anonymous

5.55 - 6/6 x 100?

3. jim_thompson5910

I think you meant to say $\Large \text{percent error} = \frac{| 5.55-6|}{|6|} \times 100\%$ right?

4. anonymous

i got -94.45...

5. jim_thompson5910

what is 5.55 - 6 equal to?

6. anonymous

-0.45

7. jim_thompson5910

|-0.45| = 0.45

8. jim_thompson5910

divide that by 6 then multiply by 100 to convert to a percentage

9. anonymous

is it b?

10. jim_thompson5910

yes

11. anonymous

i got 7.50

12. jim_thompson5910

me too

13. anonymous

ok thank you :)

14. jim_thompson5910

7.50%