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anonymous
 one year ago
Celina measured the height of a window frame as 5.55 feet, but the actual height was 6 feet. What is the percentage of error in Celina's measurement?
6.45%
7.50%
9.12%
13.33%
anonymous
 one year ago
Celina measured the height of a window frame as 5.55 feet, but the actual height was 6 feet. What is the percentage of error in Celina's measurement? 6.45% 7.50% 9.12% 13.33%

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jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1https://www.mathsisfun.com/numbers/percentageerror.html \[\large \text{percent error} = \frac{ \text{approximate value}\text{exact value}}{\text{exact value}} \ \times 100\%\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1I think you meant to say \[\Large \text{percent error} = \frac{ 5.556}{6} \times 100\%\] right?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1what is 5.55  6 equal to?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.10.45 = 0.45

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1divide that by 6 then multiply by 100 to convert to a percentage
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