## anonymous one year ago An object of mass 2.00 kg is held at a position A, a vertical height of 20.0 m above the ground. Point B is 8.00 m directly below A. Neglect air resistance and use g = 10.0 m/s2. What is the speed of the object at position B when it falls from position A? I have no idea how to go about this...

1. whpalmer4

Find the time for the object to fall from position A to position B. You can use $x = \frac{1}{2}at^2$to do so. $$x$$ represents the distance traveled, $$a$$ is the acceleration (here due to gravity, so use the value provided for $$g$$), and $$t$$ is the time. When you have found the time required for the object to fall from position A to position B, you can use $v = at$ to calculate the speed. Again, $$a=g$$ and $$t$$ is the value you found in the first part.

2. anonymous

ok, thanks!!