A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

An object of mass 2.00 kg is held at a position A, a vertical height of 20.0 m above the ground. Point B is 8.00 m directly below A. Neglect air resistance and use g = 10.0 m/s2. What is the speed of the object at position B when it falls from position A? I have no idea how to go about this...

  • This Question is Closed
  1. whpalmer4
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Find the time for the object to fall from position A to position B. You can use \[x = \frac{1}{2}at^2\]to do so. \(x\) represents the distance traveled, \(a\) is the acceleration (here due to gravity, so use the value provided for \(g\)), and \(t\) is the time. When you have found the time required for the object to fall from position A to position B, you can use \[v = at\] to calculate the speed. Again, \(a=g\) and \(t\) is the value you found in the first part.

  2. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok, thanks!!

  3. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.