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anonymous
 one year ago
Anyone here good with ellipses? If so, please help!!
Find the center, vertices, and foci of the ellipse with equation x squared divided by four hundred plus y squared divided by two hundred and fifty six = 1
A. Center: (0, 0); Vertices: (20, 0), (20, 0); Foci: (12,0), (12, 0)
B. Center: (0, 0); Vertices: (20, 0), (20, 0); Foci: (16,0), (16, 0)
C. Center: (0, 0); Vertices: (0, 20), (0, 20); Foci: (0,16), (0, 16)
D. Center: (0, 0); Vertices: (0, 20), (0, 20); Foci: (0,12), (0, 12)
I know the answer is either B or C
anonymous
 one year ago
Anyone here good with ellipses? If so, please help!! Find the center, vertices, and foci of the ellipse with equation x squared divided by four hundred plus y squared divided by two hundred and fifty six = 1 A. Center: (0, 0); Vertices: (20, 0), (20, 0); Foci: (12,0), (12, 0) B. Center: (0, 0); Vertices: (20, 0), (20, 0); Foci: (16,0), (16, 0) C. Center: (0, 0); Vertices: (0, 20), (0, 20); Foci: (0,16), (0, 16) D. Center: (0, 0); Vertices: (0, 20), (0, 20); Foci: (0,12), (0, 12) I know the answer is either B or C

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And also for Find an equation in standard form for the ellipse with the vertical major axis of length 6, and minor axis of length 4. I am pretty sure the answer is: x^2/9 + y^2/4 = 1 Is that correct?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1I have few minutes lets see if i can help u :=)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.11st) is it vertical or horizontal ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok thank you! And for the first one it is horizontal. @Nnesha

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yes right so formula for foci \[\huge\rm (h \pm c , k)\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1first of all you need to find c

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1use this equation \[\huge\rm c^2=a^2b^2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Would c = SqRt656? @Nnesha

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1remember (h,k) is the center point it's horizontal so only x values would change y would stay same no change in y values

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1no what is a^2 and b^2 ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge\rm \frac{ (xh)^2 }{ a^2 }+\frac{ (yk)^2 }{ b^2 }\] standard form of ellipse

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wouldn't a^2 = 256 and b^2 = 400?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1okay for ellipse a= bigger number if a is under the x then it's horizontal and if a is under y then it would be vertical

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1so now what are the foci points ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Forgot the ( ) sorry

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[(\pm 12,0)\] looks great should be plus minus sign

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes that's what I meant, sorry.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So my answer would actually be A. Ok, thanks! Could you help me with the 2nd one?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And also with this one: The rectangular piece of property measures 10 mi by 4 mi. Find an equation for the ellipse if the path is to touch the center of the property line on all 4 sides. I believe my answer would be: x^2/25 + y^2/4 = 1 But I just wanted to make sure.

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\(\color{blue}{\text{Originally Posted by}}\) @jdoherty And also for Find an equation in standard form for the ellipse with the vertical major axis of length 6, and minor axis of length 4. I am pretty sure the answer is: x^2/9 + y^2/4 = 1 Is that correct? \(\color{blue}{\text{End of Quote}}\) *vertical*

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1if ellipse is vertical then bigger number supposed to be under x or y ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yes right try to draw points on the paper

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok :( Are you free at all tomorrow?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@saseal Could you help with the other two questions?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.01. The rectangular piece of property measures 10 mi by 4 mi. Find an equation for the ellipse if the path is to touch the center of the property line on all 4 sides. I believe my answer would be: x^2/25 + y^2/4 = 1 But I just wanted to make sure. 2. Find an equation in standard form for the ellipse with the vertical major axis of length 6, and minor axis of length 4. I am pretty sure the answer is: x^2/9 + y^2/4 = 1 Is that correct?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0first one is correct...2nd one is debatable because the question is not very specified

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if they specifed the major axis is x and minor is y then you are correct

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hmm...how could I determine for sure?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hmm you are wrong...it says vertical major axis

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh ok. So that would make the y axis the major axis?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh wait. would it be x^2/4 + y^2/9 = 1? @saseal

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Could you help me a couple more questions? I kind of am just getting this stuff. Lol. @saseal

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Find the vertices and foci of the hyperbola with equation x squared over nine minus y squared over sixteen = 1 This is for Hyperbolas...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ x^2 }{ 3^2 }  \frac{ y^2 }{ 4^2 } = 1\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0now it becomes y^2/4^2  x^2/3^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ y^2 }{ 4^2 }  \frac{ x^2 }{ 3^2 } =1\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok so then what can I do?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you know where thid hyperbola opens open?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Not really like when it's graphed?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439004618140:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok so they open up where the two points are? Like the end points of the opening?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0kinda...abit like parabola x2
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