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anonymous
 one year ago
help please
anonymous
 one year ago
help please

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What is the area, in square feet, of the shaded region? Enter your answer in the box. square feet What is the area, in square feet, of the nonshaded region? Enter your answer in the box. square feet

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.2So for the shaded area we need to divide it into three sections two rectangles and a triangle to determine the total area

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.2The first rectangle we will do is the bottom A=lw Where A is area, l is length and w is width So A =8x2=?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so i just multiply 8*2

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.2Yes that will give you the area of the first rectangle so one of three parts of the shaded section

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.2Yep so that's the first one so let's do the second rectangle or the middle sort of section

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.2So the second rectangle A=lw =(1)(8+2) We get the 8+2 because the side length is split into two parts so we just have to put them together

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so just add 8 plus 2

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.2Yep for that's all you have to do for that one cause the side length is 1

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.2So the last part of the shaded area is the triangle and yes 10 is right for that second rectangle

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.2A=bh/2 Where b is the base (8221)=3 and h is the height 8+2=10 So A= (3)(10)/2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry i dont understand what that means

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.2The area of a triangle is represented by Area= base times height all divided by two A=bh/2 A=(3)(10)/2 A=30/2 A=15

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so i divide them all?

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.2There are three parts to the shaded area so to find the total area of the shaded section so the total area=16+10+15

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh ok so just add all thre of those

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.2Yes if you add those three together you will get the total area of the shaded area

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what about the non shaded area

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.2So to find the area of the no shaded area first we need to find the total area of the square A=lw A=(8)(16)

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.2You would multiply them together

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.2Yes so that's the area of both the non shaded area and the shaded area so you just need to subtract the shaded area from that total area to find the non shaded area So 12841= the nonshaded area

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is the shaded area 41?

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.2Yes that 87 would be the area for the non shaded section

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.2The shaded area would be 41

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.2No problem! Happy to help!
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