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Use\[v-e+f=2\]where v is no. of vertices, e is no. of edges, f is no of faces.

so 9- ? + 5 = 2 ?

Figure has 5 square faces PLUS 4 triangular faces, so 9 faces in total.

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ut oh, I'm confused.

What don't you understand?

oh wait, 9+9 is 18

So 18 edges, I think :o

I think so, because E is what I'm suppose to find out

That's right. Go ahead. What do you get?

20 edges?

so e will cancel out? v+f=2

I don't do too well with just variables :o

It's OK. Work with them just as you would work with numbers.

What do you get when you add e to BOTH sides of the equation?

v+ f(e)= 2 ?

ooh yes okay

Yep yep, that part makes sense

we subtract 2 from both sides, but I'm not too sure how that will look

That's right. Let's write it out just like before.\[v+f-2=2+e-2\]Does that make sense?

ohh okay, I understand

Almost there. Now, simplify the right hand side. What will the equation look like?

we subtract 2 again right?

Yup. There's a 2 and a -2 on the right hand side. They 'cancel each other out'.

so v + f - 2 = e ?

9+ 9 ? Because earlier you said 4 faces and 5 faces, which is 9 :o

But you're forgetting something. v=9 and f=9 so we have\[e=v+f-2\]\[e=9+9-2\]\[e=?\]

18-2 = 16

Yayyyy!

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