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anonymous
 one year ago
Phyiscs question
anonymous
 one year ago
Phyiscs question

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i know i have to use v=d/t , i was getting the wrong answer

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0I'm sorry, I'm not good with astronomy, since I have studied nuclear physics mainly when I was at university

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1\(\large c_{est} = \frac{d}{t} =\frac{3 \times 10^{11}}{19 \times 60} = ???\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@IrishBoy123 what confused me about the question is dont u have to measure the distance from going to coming ? so like take the distance and timising by 2 ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what makes this question different?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1**distance from going to coming** that to me does not really have any meaning. this is a simple skit about the fact that light itself has a "finite" speed. so, the amateur astronomers assumed instantaneous light , and worked out something different.!? not sure this helps too much.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@IrishBoy123 can u help me with this one ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@IrishBoy123 u there?

danica518
 one year ago
Best ResponseYou've already chosen the best response.0okay diverging lens so the ray are spreading out

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can u show me some steps

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@shreehari499 http://assets.openstudy.com/updates/attachments/55c59591e4b0c7f4a97933d8ilovehw1439062524938jdjdjjd.jpg
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