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anonymous
 one year ago
An advertising ﬁrm has an old computer that can prepare a whole mailing in 6 hours.
With the help of a newer model the job is complete in 2 hours. How long would it
take the newer model to do the job alone?
anonymous
 one year ago
An advertising ﬁrm has an old computer that can prepare a whole mailing in 6 hours. With the help of a newer model the job is complete in 2 hours. How long would it take the newer model to do the job alone?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got 1/6 +1/x = 1/2 then 1/x = 1/2 1/6 = 1/3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got 1/x = 1/3 what's next?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0your goal is to solve \(x\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeap I know but how would I translate 1/x to x=3 I know 3 is the answer but how will I get there

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.01/x = 1/3 flip both sides and get x/1 = 3/1 which is same as x = 3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You just flip it? No math explanation?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0flipping is mathematical. for nonzero real numbers, we have : \[\dfrac{a}{b} = \dfrac{c}{d} \implies \dfrac{b}{a}=\dfrac{d}{c}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh I thought when you flip it becomes \[x^1 = 3\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait a minute I could've use cross multiply!!!

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0Yes you could do that too

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah thank you for lending me a hand. I'm doing crash course for my engineering math exit. Thank you!

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0np, good luck with the course!
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