At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
can you help? @swamijatin2
what we have to find perimeter or area
lol wrong thing sorry
I need a (side a); C(angle c); and B(angle b)
or well that doesnt have to be a right triangle but
how do i do this
draw a triangle that looks reasonably like this one then use the law of cosines
i have a triangle but how do i use the law of cosines (i know what it is just not how to do it)
\[a^2=b^2+c^2-2bc\cos(A)\] \[a^2=11^2+7^2-2\times 11\times 7\cos(51^\circ)\] and a calculator
To solve the traingle we need to find remaining side a and angles B and C. Use law of cosines a2 = b2 + c2 - 2bc cosA a2 = (11)2 + (7)2 - 2(11)(7) cos(51) a2 = 121 + 49 - 154 cos(51) a2 = 170 - 154(0.629) a2 = 170 - 96.866 a2 = 73.134 a = 8.55
i got that ok so how about the and C
B and C angles
Now use law of sines sinA/a = sinB/b sin(51)/ 8.55 = sin(B)/11 sin(B) = 11[sin(51)/ 8.55] sin(B) = 11[0.777/8.55] B = sin-1(0.999) B = 87.43°
ok and C?
Sum of angles in triangle = 180° A + B + C = 180 C = 180 - (A + B) C = 180 - (51 + 87.43) C = 180 - 138.43 C = 41.57°
because none of those are my answers
then you are incorrect anywhere
did u get the answers
8.5 is a which is only for one answer choice where B = 85.9 and C = 39.1
a ≈ 12.8, C ≈ 39.1, B ≈ 89.9 a ≈ 8.5, C ≈ 39.1, B ≈ 89.9 No triangles possible a ≈ 12.8, C ≈ 43.1, B ≈ 85.9
you r correct but according to question we have to do
please finish helping me @swamijatin2
we have done a lot but it doesn't match my answer choices
can you re-post the question and the answer you got? It would take a long time to read through all of the posts up above.
sure hold on
Solve the triangle. A = 51°, b = 11, c = 7
Work From above: a2 = b2 + c2 - 2bc cosA a2 = (11)2 + (7)2 - 2(11)(7) cos(51) a2 = 121 + 49 - 154 cos(51) a2 = 170 - 154(0.629) a2 = 170 - 96.866 a2 = 73.134 a = 8.55 Now use law of sines sinA/a = sinB/b sin(51)/ 8.55 = sin(B)/11 sin(B) = 11[sin(51)/ 8.55] sin(B) = 11[0.777/8.55] B = sin-1(0.999) B = 87.43° Sum of angles in triangle = 180° A + B + C = 180 C = 180 - (A + B) C = 180 - (51 + 87.43) C = 180 - 138.43 C = 41.57°
My answer choices are: a ≈ 12.8, C ≈ 39.1, B ≈ 89.9 a ≈ 8.5, C ≈ 39.1, B ≈ 89.9 No triangles possible a ≈ 12.8, C ≈ 43.1, B ≈ 85.9
so... what do we do?
side a is correct. a= 8.55 redo your work for angle B
the problem is when you do the work for angle B, you need lots of decimals of accuracy. for side a, don't round it to 8.55. use all the digits your calculator has.
it might be more accurate to first find angle C sin C = (7*sin51)/8.548956649
what do you get for angle B i got the same answer
I got 0.63633750 Radians for C?
sin C = 0.63633750 C= asin( 0.63633750 ) = 39.519 deg
summarizing a= 8.55, b= 11, c= 7 A= 51, B= 89.5, C= 39.5 the best match to your choices is choice B
if we use a=8.6 (round from 8.55) we would get C= 39.2 and B= 89.8 which is even closer to choice B.
because they use ≈ which means approximately it is reasonable to pick choice B. And the other choices are not "in the ball park"