anonymous
  • anonymous
Which equation could be used to solve this problem? The sum of two consecutive integers is 141. Find the integers. A. n + 1= 141 B. 2n + 2 = 141 C. 2n = 141 D. 2n + 1 = 141
Mathematics
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
@Michele_Laino
anonymous
  • anonymous
i'm thinking D @Michele_Laino
anonymous
  • anonymous
@Haseeb96

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More answers

Michele_Laino
  • Michele_Laino
if n is an integer, then its consecutive is n+1, so we can write this: \[\Large n + \left( {n + 1} \right) = 141\] please simplify
anonymous
  • anonymous
then A
Michele_Laino
  • Michele_Laino
no, since you have to compute this sum: \[\Large n + \left( {n + 1} \right)\]
anonymous
  • anonymous
then has to be C
Michele_Laino
  • Michele_Laino
sorry, C) can't be the right option. Hint: \[\Large n + \left( {n + 1} \right) = n + n + 1\]
anonymous
  • anonymous
BBBBBBBBBB
Michele_Laino
  • Michele_Laino
no, since we have 1 not 2
anonymous
  • anonymous
whaaaaat. then its D
Michele_Laino
  • Michele_Laino
yes! it is D, we can write this: \[\Large n + \left( {n + 1} \right) = n + n + 1 = 2n + 1 = 141\]
anonymous
  • anonymous
i was thinking D if you read my 2nd comment but thank you @Michele_Laino . :)
Michele_Laino
  • Michele_Laino
sorry!
anonymous
  • anonymous
np. >,<
Michele_Laino
  • Michele_Laino
:)

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