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mathmath333
 one year ago
Counting Problem
mathmath333
 one year ago
Counting Problem

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mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0\(\large \color{black}{\begin{align} & \normalsize \text{How many 3digit even numbers can be made using the digits}\hspace{.33em}\\~\\ & \normalsize \text{1, 2, 3, 4, 6, 7}\quad \text{ if no digit is repeated?}\hspace{.33em}\\~\\ \end{align}}\)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.3let the number be abc, at 'c', there can be one of the 3 even numbers. at b, there can be remaining 5 numbers at a, there can be remaining 4 numbers. total numbers = \(3\times 5 \times 4 \)

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0at b, there can be remaining 5 numbers where does 5 come from ???

hartnn
 one year ago
Best ResponseYou've already chosen the best response.3out of these 6 numbers, 1,2,3,4,6,7 one is used in the units place, so there are 5 numbers to choose from.

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0but even numbers are three (2,4,6) not one

hartnn
 one year ago
Best ResponseYou've already chosen the best response.3yes, thats why '3' is multiplied, not one. but you will use only one of the 3 even numbers in the unit's place right?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.3if we could repeat the numbers, then we would have got 6 options at both a and b position, then it would be 6*6*3

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0but why are u starting/counting from unit's digit rather than hundred's digit

hartnn
 one year ago
Best ResponseYou've already chosen the best response.3because there is restriction at unit's place and not at hundred's place

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0answer is 60 (given)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.3if we say there are 6 options at hundreds place, that would be incorrect, because one of them, an even number, must be used at unit's place.

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0ohk i see ur logic

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2Alternatively, you may see that total possible 3 digit integers with distinct digits is \(6*5*4 = 120\). However exactly half of these odd, so \(120/2 = 60\) are even.

terenzreignz
 one year ago
Best ResponseYou've already chosen the best response.0You lost me... long ago. But I'm back But you also lost me at "exactly half of these are odd" Really? :D

hartnn
 one year ago
Best ResponseYou've already chosen the best response.3we can say exactly half of these are odd, only because half of the given digits are odd! otherwise, that statement won't hold true.

terenzreignz
 one year ago
Best ResponseYou've already chosen the best response.0Sorry... I keep missing that there's no 5 in the set. Dang misleading questions...

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2the given set has some sort of symmetry with respect to even/odd which we can use to our advantage :)
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