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anonymous

  • one year ago

Solve the given number problem. The sum of three consecutive even integers is –114. What is the least of these numbers? A. 40 B. –36 C. –40 D. –44

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  1. anonymous
    • one year ago
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    i'm pretty sure its B @Michele_Laino

  2. anonymous
    • one year ago
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    MISTYYYY. :D:D:D:D

  3. misty1212
    • one year ago
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    HI!! it is easy to check if it is B!

  4. misty1212
    • one year ago
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    add \(-36+(-35)+(-34)\) and see if you get \(-144\)

  5. misty1212
    • one year ago
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    but you don't, you get \(-105\) so it is not that one

  6. anonymous
    • one year ago
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    darn. :P

  7. welshfella
    • one year ago
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    you can form an equation to solve this one

  8. anonymous
    • one year ago
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    someone taged me in one of my closed post's brb

  9. misty1212
    • one year ago
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    none of these are correct btw

  10. misty1212
    • one year ago
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    http://www.wolframalpha.com/input/?i=-40-39-38

  11. welshfella
    • one year ago
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    n + n + 2 + n+ 4 = -114 3n + 6 = -114 can you continue to fids n?

  12. misty1212
    • one year ago
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    oops consecutive EVEN integers i should learn how to read

  13. welshfella
    • one year ago
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    lol - it happens!

  14. anonymous
    • one year ago
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    sorry open study "lost conection"

  15. anonymous
    • one year ago
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    i'm pretty sure its C then

  16. welshfella
    • one year ago
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    yes correct

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