Amir pitches a baseball at an initial height of 6 feet, with a velocity of 73 feet per second. If the batter misses, about how long does it take the ball hit the ground? Hint: Use H(t) = −16t2 + vt + s. 4.64 seconds 2.94 seconds 2.28 seconds 0.08 second

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Amir pitches a baseball at an initial height of 6 feet, with a velocity of 73 feet per second. If the batter misses, about how long does it take the ball hit the ground? Hint: Use H(t) = −16t2 + vt + s. 4.64 seconds 2.94 seconds 2.28 seconds 0.08 second

Mathematics
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when the ball hits the ground H(t) = 0
so plug in 0 for H(t) , 6 for s and 73 for v, then solve for t.
h(0)=-16t^2+73t+6? @welshfella

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then i would solve for t which i will do in a sec
t=250/73?
i got a different value
250/73 = 3.42
did you use the quadratic formula?
x = [ -73 +/- sqrt(73^2 - 4*-16*6) ] / (2*-16)
oh ok its not different you just divided lol
what would i do after?
= (-73 - 75.58) / -32 = 4.64
73^2 - 4*-16*6 comes to 5713 and sqrt 5713 = 75.58
- the other root is 0.08 which we can ignore
ok
- sorry it was -0.08 which of course we can ignore
ok so the answer would be 4.64? based on what you have explained/said
yes
the other root is negative - the correct time is 4.64 seconds
ty! :)
yw

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