vera_ewing
  • vera_ewing
Chem question
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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Rushwr
  • Rushwr
Hey what is the answer u got ?
Rushwr
  • Rushwr
how did u find that! Tell me how u did it?
vera_ewing
  • vera_ewing
Wait, is the reaction at equilibrium?

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More answers

sweetburger
  • sweetburger
Basically you are solving for Q and then your answer revolves around what answer you get for Q.
Australopithecus
  • Australopithecus
vera_ewing
  • vera_ewing
I got 4.3 x 10^-2, though...
Rushwr
  • Rushwr
\[N _{2}O _{4} => 2NO _{2}\]
Rushwr
  • Rushwr
So first write and equation for Kc.
Australopithecus
  • Australopithecus
http://www.800mainstreet.com/7/0007-007-Equi_exp_k.html see this and see the section: "What does an equilibrium constant tell"
vera_ewing
  • vera_ewing
Okay, and then what?
sweetburger
  • sweetburger
Well the Kc given here states that the reactants are far more favored as it is far less than 1.
Rushwr
  • Rushwr
\[K _{c} =\frac{ [NO _{2}]^{2} }{ [N _{2} O _{4}]}\]
vera_ewing
  • vera_ewing
Yeah don't you get 4.3 x 10^-2 when you do it that way?
Rushwr
  • Rushwr
since they have given us some concentrations calculate Kc for the given concentrations!
Australopithecus
  • Australopithecus
4.3 x 10^-2 does not equal Kc therefore you can conclude that the reaction is not at equilibrium
Rushwr
  • Rushwr
I get 4.5 x 10^-2
vera_ewing
  • vera_ewing
How? Can you show me your work?
sweetburger
  • sweetburger
Alright lets just set it up what it would look like to solve for Q in this situation. [.15]^2/[.5]= .045 which is 4.5x10^-2 is what i got
vera_ewing
  • vera_ewing
Ohhh I see. I messed up.
vera_ewing
  • vera_ewing
Thanks so much.
sweetburger
  • sweetburger
which is in fact larger than the given Kc so what would have to happen to reach equilibrium?
Australopithecus
  • Australopithecus
Check out that page I linked
Rushwr
  • Rushwr
\[Kc = 0.15^{2}/ 0.5\]
Rushwr
  • Rushwr
So it's gonna be D !
Australopithecus
  • Australopithecus
and the image I posted
sweetburger
  • sweetburger
yes I agree it should be D.

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