moazzam07
  • moazzam07
Question 4: Two equations are shown: Equation 1: 3 4 (x−12)=12 Equation 2: 3 4 y−12=12 Solve each equation. Then, enter a number in each box to make this statement true.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
yea?
moazzam07
  • moazzam07
3/4y−12=12
moazzam07
  • moazzam07
3/4(x-12)=12

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More answers

moazzam07
  • moazzam07
i dont know how to solve it
anonymous
  • anonymous
\[\frac{ 3 }{ 4 }y-12=12\] and\[\frac{ 3 }{ 4 }(x-12)=12\]
moazzam07
  • moazzam07
yes that
moazzam07
  • moazzam07
how do i solve it
anonymous
  • anonymous
we add 12 to both sides for the first equation
anonymous
  • anonymous
\[\frac{ 3 }{ 4 y}-12+12 = 12+12\] simplifed to \[\frac{ 3 }{ 4 }y =24\]
moazzam07
  • moazzam07
yes
anonymous
  • anonymous
multiply both sides by 4 to cancel the denominator we get 3y=96
moazzam07
  • moazzam07
ok so 3y = 96 is left
anonymous
  • anonymous
divide both sides by 3
moazzam07
  • moazzam07
1y = 31
anonymous
  • anonymous
32
moazzam07
  • moazzam07
y=32
anonymous
  • anonymous
yea
moazzam07
  • moazzam07
:O ok
anonymous
  • anonymous
2nd part try doing it the same way
moazzam07
  • moazzam07
ok
moazzam07
  • moazzam07
i ended up with 3x = 6
moazzam07
  • moazzam07
then i divided both sides by 3
anonymous
  • anonymous
lemme show ya...
moazzam07
  • moazzam07
x=2?
anonymous
  • anonymous
\[\frac{ 3 }{ 4 } (x-12)=12\] multiply 4 on both sides we get \[3(x-12) = 48\]
moazzam07
  • moazzam07
oh i added 12 to both sides
moazzam07
  • moazzam07
now i add 12 to both sides?
anonymous
  • anonymous
expand \[3(x-12)\]
moazzam07
  • moazzam07
3x - 36
anonymous
  • anonymous
3x-36=48 now add 36 to both sides
moazzam07
  • moazzam07
3x=84
anonymous
  • anonymous
yes
moazzam07
  • moazzam07
x=28
anonymous
  • anonymous
correct
moazzam07
  • moazzam07
OMG you are awesome thank you sooooo much
anonymous
  • anonymous
yw
moazzam07
  • moazzam07
x=28

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