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anonymous
 one year ago
FAN AND MEDAL
Amir pitches a baseball at an initial height of 6 feet, with a velocity of 73 feet per second. If the batter misses, about how long does it take the ball hit the ground?
Hint: Use H(t) = −16t^2 + vt + s.
4.64 seconds
2.94 seconds
2.28 seconds
0.08 second
anonymous
 one year ago
FAN AND MEDAL Amir pitches a baseball at an initial height of 6 feet, with a velocity of 73 feet per second. If the batter misses, about how long does it take the ball hit the ground? Hint: Use H(t) = −16t^2 + vt + s. 4.64 seconds 2.94 seconds 2.28 seconds 0.08 second

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@queenoftokyo @william22 @enchanted_bubbles @rational @triciaal @yomamabf @uybuyvf @ikram002p @oldrin.bataku @poopsiedoodle @Astrophysics @satellite73 @DullJackel09 @freckles @ganeshie8 @hartnn @Hero @JFraser @Kainui @kropot72 @Luigi0210 @zepdrix @campbell_st @vera_ewing

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@hartnn help please!

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2just plug in the values given in the equation, H(t) = −16t^2 + vt + s. here s= initial height = 6 v = velocity = 73 and the height at ground level H(t) = 0 only 't' is unknown!

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2you'll get a quadratic in 't' let me know if you have any doubts in solving that?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2did u plug in values? what did u get?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2now use quadratic formula to solve that!

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2Compare your quadratic equation with \(ax^2+bx+c=0\) find \[a=...?\\b=...?\\c=...?\\\] \[ \\ \sqrt{b^24ac}=...?\] then the two roots of x are: \(\huge{x_{1,2}=\frac{b \pm \sqrt{b^24ac}}{2a}}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh ok can you wait for me to solve it?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2sure, just gave you the steps :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0alright I'm almost done
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