## anonymous one year ago FAN AND MEDAL Amir pitches a baseball at an initial height of 6 feet, with a velocity of 73 feet per second. If the batter misses, about how long does it take the ball hit the ground? Hint: Use H(t) = −16t^2 + vt + s. 4.64 seconds 2.94 seconds 2.28 seconds 0.08 second

1. anonymous

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2. anonymous

3. hartnn

just plug in the values given in the equation, H(t) = −16t^2 + vt + s. here s= initial height = 6 v = velocity = 73 and the height at ground level H(t) = 0 only 't' is unknown!

4. hartnn

you'll get a quadratic in 't' let me know if you have any doubts in solving that?

5. anonymous

how do i find t?

6. hartnn

did u plug in values? what did u get?

7. anonymous

-16t^2+73t+6=0

8. hartnn

now use quadratic formula to solve that!

9. hartnn

Compare your quadratic equation with $$ax^2+bx+c=0$$ find $a=...?\\b=...?\\c=...?\\$ $\\ \sqrt{b^2-4ac}=...?$ then the two roots of x are: $$\huge{x_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}$$

10. anonymous

oh ok can you wait for me to solve it?

11. triciaal

don't tag me anymore

12. hartnn

sure, just gave you the steps :)

13. anonymous

y? @triciaal

14. anonymous

alright I'm almost done

15. anonymous

is it 4.64? @hartnn

16. hartnn

yes! correct :)

17. anonymous

thank you!!

18. hartnn

welcome ^_^