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anonymous

  • one year ago

Solve the system graphically and algebrically

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  1. anonymous
    • one year ago
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    x+y=1 y=2/3x-4

  2. anonymous
    • one year ago
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    @freckles

  3. anonymous
    • one year ago
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    You're looking for x and y?

  4. anonymous
    • one year ago
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    I dont know:(

  5. anonymous
    • one year ago
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    Okay, well I believe you are because it says solve. There are two options here. Do you want the easy way or the harder way? (They aren't always easy versus hard, it just happens that one is a lot simpler in this instance)

  6. anonymous
    • one year ago
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    easy way:)

  7. anonymous
    • one year ago
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    Okay for the easy way in this instance, we will go with substitution. Do you know what that is?

  8. anonymous
    • one year ago
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    yes.

  9. anonymous
    • one year ago
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    Okay so use substitution by plugging in what the second equation gives you for "y" into the first equation. It should look like this: \[x+2/3x-4=1\] You can solve this because it is one variable.

  10. anonymous
    • one year ago
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    So solve for x

  11. anonymous
    • one year ago
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    1^2/3x=5 ??

  12. anonymous
    • one year ago
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    I'm not sure where you got one from. Step one: add 4 to both sides. You get: \[x+2/3x=5\]

  13. anonymous
    • one year ago
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    Step two: combine like terms. You get:\[5/3x=5\]

  14. anonymous
    • one year ago
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    Do you get it so far?

  15. anonymous
    • one year ago
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    yes:)

  16. anonymous
    • one year ago
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    Step three: multiply each side by three (to get rid of the denominator): \[5x=15\]

  17. anonymous
    • one year ago
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    Now what do you do?

  18. anonymous
    • one year ago
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    x=3

  19. anonymous
    • one year ago
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    Correct. Now, plug in what you just found for "x" into the first equation. Your equation should look like this now: \[3+y=1\]

  20. anonymous
    • one year ago
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    ok:) Now what do we do?

  21. anonymous
    • one year ago
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    Solve for "y" can you do that part by yourself?

  22. anonymous
    • one year ago
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    i suppose. Is it y=-3x-1?

  23. anonymous
    • one year ago
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    Nope. You plugged in an "x" for no reason. From your equation 3+y=1, all you have to do is subtract 3 from each side. You end up with: \[y=-2\]

  24. anonymous
    • one year ago
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    Alright:)

  25. anonymous
    • one year ago
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    Get that?

  26. phi
    • one year ago
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    btw the question asks Solve the system graphically and algebarically it wants you to solve this problem both ways.

  27. anonymous
    • one year ago
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    Okay so now we know that you have x=3 and y=-2. I don't have any way to graph it myself, but I plugged this into wolfram alpha so look at this graph: http://www.wolframalpha.com/input/?i=x%2By%3D1%2C+y%3D%282%2F3%29x-4

  28. anonymous
    • one year ago
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    Thank you! So, we solved it graphically, what would be the 'algebracially' part?

  29. anonymous
    • one year ago
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    Well, since we found x=3 and y=-2, we can (if you want) turn it into a coordinate. I'm not sure if that's what your question wants, but based on the fact you need to graph it also, then turn it into a coordinate. It'll be (3,-2)

  30. anonymous
    • one year ago
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    I'm guessing that your problem also wants you to graph the two equations.

  31. anonymous
    • one year ago
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    But that would be your answer.

  32. anonymous
    • one year ago
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    tHANKS<3 Can I ask another??

  33. anonymous
    • one year ago
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    Sure but I'm not sure if I'll be able to answer everything.

  34. anonymous
    • one year ago
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    it's fine.

  35. anonymous
    • one year ago
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    |dw:1439058745006:dw| Solve and graph

  36. anonymous
    • one year ago
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    Let me see what I can do, give me a second. I might be able to help, but maybe not.

  37. anonymous
    • one year ago
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    ok,if not, we can always call @phi lol

  38. anonymous
    • one year ago
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    Yeah I'm sorry I kinda remember how to do this, but I'm not sure enough to help you. I don't want you to get it wrong.

  39. anonymous
    • one year ago
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    it's cool :) Thanks anywayss

  40. anonymous
    • one year ago
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    No problem. Good luck!

  41. phi
    • one year ago
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    \[|x-1| -3 \le 1 \] first add (write) +3 on both sides

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