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anonymous
 one year ago
Solve the system graphically and algebrically
anonymous
 one year ago
Solve the system graphically and algebrically

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You're looking for x and y?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, well I believe you are because it says solve. There are two options here. Do you want the easy way or the harder way? (They aren't always easy versus hard, it just happens that one is a lot simpler in this instance)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay for the easy way in this instance, we will go with substitution. Do you know what that is?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay so use substitution by plugging in what the second equation gives you for "y" into the first equation. It should look like this: \[x+2/3x4=1\] You can solve this because it is one variable.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm not sure where you got one from. Step one: add 4 to both sides. You get: \[x+2/3x=5\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Step two: combine like terms. You get:\[5/3x=5\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you get it so far?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Step three: multiply each side by three (to get rid of the denominator): \[5x=15\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Correct. Now, plug in what you just found for "x" into the first equation. Your equation should look like this now: \[3+y=1\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok:) Now what do we do?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Solve for "y" can you do that part by yourself?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i suppose. Is it y=3x1?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Nope. You plugged in an "x" for no reason. From your equation 3+y=1, all you have to do is subtract 3 from each side. You end up with: \[y=2\]

phi
 one year ago
Best ResponseYou've already chosen the best response.0btw the question asks Solve the system graphically and algebarically it wants you to solve this problem both ways.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay so now we know that you have x=3 and y=2. I don't have any way to graph it myself, but I plugged this into wolfram alpha so look at this graph: http://www.wolframalpha.com/input/?i=x%2By%3D1%2C+y%3D%282%2F3%29x4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you! So, we solved it graphically, what would be the 'algebracially' part?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well, since we found x=3 and y=2, we can (if you want) turn it into a coordinate. I'm not sure if that's what your question wants, but based on the fact you need to graph it also, then turn it into a coordinate. It'll be (3,2)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm guessing that your problem also wants you to graph the two equations.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But that would be your answer.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0tHANKS<3 Can I ask another??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sure but I'm not sure if I'll be able to answer everything.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439058745006:dw Solve and graph

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Let me see what I can do, give me a second. I might be able to help, but maybe not.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok,if not, we can always call @phi lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah I'm sorry I kinda remember how to do this, but I'm not sure enough to help you. I don't want you to get it wrong.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it's cool :) Thanks anywayss

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No problem. Good luck!

phi
 one year ago
Best ResponseYou've already chosen the best response.0\[x1 3 \le 1 \] first add (write) +3 on both sides
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