anonymous
  • anonymous
Solve the system graphically and algebrically
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
x+y=1 y=2/3x-4
anonymous
  • anonymous
@freckles
anonymous
  • anonymous
You're looking for x and y?

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anonymous
  • anonymous
I dont know:(
anonymous
  • anonymous
Okay, well I believe you are because it says solve. There are two options here. Do you want the easy way or the harder way? (They aren't always easy versus hard, it just happens that one is a lot simpler in this instance)
anonymous
  • anonymous
easy way:)
anonymous
  • anonymous
Okay for the easy way in this instance, we will go with substitution. Do you know what that is?
anonymous
  • anonymous
yes.
anonymous
  • anonymous
Okay so use substitution by plugging in what the second equation gives you for "y" into the first equation. It should look like this: \[x+2/3x-4=1\] You can solve this because it is one variable.
anonymous
  • anonymous
So solve for x
anonymous
  • anonymous
1^2/3x=5 ??
anonymous
  • anonymous
I'm not sure where you got one from. Step one: add 4 to both sides. You get: \[x+2/3x=5\]
anonymous
  • anonymous
Step two: combine like terms. You get:\[5/3x=5\]
anonymous
  • anonymous
Do you get it so far?
anonymous
  • anonymous
yes:)
anonymous
  • anonymous
Step three: multiply each side by three (to get rid of the denominator): \[5x=15\]
anonymous
  • anonymous
Now what do you do?
anonymous
  • anonymous
x=3
anonymous
  • anonymous
Correct. Now, plug in what you just found for "x" into the first equation. Your equation should look like this now: \[3+y=1\]
anonymous
  • anonymous
ok:) Now what do we do?
anonymous
  • anonymous
Solve for "y" can you do that part by yourself?
anonymous
  • anonymous
i suppose. Is it y=-3x-1?
anonymous
  • anonymous
Nope. You plugged in an "x" for no reason. From your equation 3+y=1, all you have to do is subtract 3 from each side. You end up with: \[y=-2\]
anonymous
  • anonymous
Alright:)
anonymous
  • anonymous
Get that?
phi
  • phi
btw the question asks Solve the system graphically and algebarically it wants you to solve this problem both ways.
anonymous
  • anonymous
Okay so now we know that you have x=3 and y=-2. I don't have any way to graph it myself, but I plugged this into wolfram alpha so look at this graph: http://www.wolframalpha.com/input/?i=x%2By%3D1%2C+y%3D%282%2F3%29x-4
anonymous
  • anonymous
Thank you! So, we solved it graphically, what would be the 'algebracially' part?
anonymous
  • anonymous
Well, since we found x=3 and y=-2, we can (if you want) turn it into a coordinate. I'm not sure if that's what your question wants, but based on the fact you need to graph it also, then turn it into a coordinate. It'll be (3,-2)
anonymous
  • anonymous
I'm guessing that your problem also wants you to graph the two equations.
anonymous
  • anonymous
But that would be your answer.
anonymous
  • anonymous
tHANKS<3 Can I ask another??
anonymous
  • anonymous
Sure but I'm not sure if I'll be able to answer everything.
anonymous
  • anonymous
it's fine.
anonymous
  • anonymous
|dw:1439058745006:dw| Solve and graph
anonymous
  • anonymous
Let me see what I can do, give me a second. I might be able to help, but maybe not.
anonymous
  • anonymous
ok,if not, we can always call @phi lol
anonymous
  • anonymous
Yeah I'm sorry I kinda remember how to do this, but I'm not sure enough to help you. I don't want you to get it wrong.
anonymous
  • anonymous
it's cool :) Thanks anywayss
anonymous
  • anonymous
No problem. Good luck!
phi
  • phi
\[|x-1| -3 \le 1 \] first add (write) +3 on both sides

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