anonymous
  • anonymous
∆ABC is plotted on a coordinate plane. If ∆ABC rotates 90° clockwise around point C, what are the coordinates of A'? (0, 2) (4, 6) (7, 6) (8, 2)
Geometry
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
muscrat123
  • muscrat123
Do u have graph paper?
muscrat123
  • muscrat123
Or is there a graph with the question?
anonymous
  • anonymous
yes

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

muscrat123
  • muscrat123
Which one?
anonymous
  • anonymous
its a graph with a question
anonymous
  • anonymous
muscrat123
  • muscrat123
Hang on
muscrat123
  • muscrat123
it wont let me open the attachment
anonymous
  • anonymous
Say, (a1,a2) and (c1,c2) be the co-ordinates of the points A and C respectively. Say the origin is denoted by O. The vectors OA and OC are given by a1 + ia2 and c1 + ic2 resp. The vector CA is given by (a1-c1)+ i(a2-c2) This segment rotates clockwise by 90 degrees around C. This operation is the same as multiplication by -i. So, the rotated vector is (a2-c2) - i(a1-c1) , call this CA' , A' is the new position of A. Therefore the vector OA' is given by (a2-c2) - i(a1-c1) + c1 + ic2 = (a2-c2+c1) + i(c2 + c1 - a2) [what we did was simply OA' = CA' + OC, vector addition] So, the new position of A, that is A' has the co-ordinates ((a2-c2+c1),(c2+c1-a2)) Plug in the values given in your specific problem.
anonymous
  • anonymous
thank u 💙

Looking for something else?

Not the answer you are looking for? Search for more explanations.