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anonymous
 one year ago
∆ABC is plotted on a coordinate plane. If ∆ABC rotates 90° clockwise around point C, what are the coordinates of A'?
(0, 2)
(4, 6)
(7, 6)
(8, 2)
anonymous
 one year ago
∆ABC is plotted on a coordinate plane. If ∆ABC rotates 90° clockwise around point C, what are the coordinates of A'? (0, 2) (4, 6) (7, 6) (8, 2)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do u have graph paper?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Or is there a graph with the question?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0its a graph with a question

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it wont let me open the attachment

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Say, (a1,a2) and (c1,c2) be the coordinates of the points A and C respectively. Say the origin is denoted by O. The vectors OA and OC are given by a1 + ia2 and c1 + ic2 resp. The vector CA is given by (a1c1)+ i(a2c2) This segment rotates clockwise by 90 degrees around C. This operation is the same as multiplication by i. So, the rotated vector is (a2c2)  i(a1c1) , call this CA' , A' is the new position of A. Therefore the vector OA' is given by (a2c2)  i(a1c1) + c1 + ic2 = (a2c2+c1) + i(c2 + c1  a2) [what we did was simply OA' = CA' + OC, vector addition] So, the new position of A, that is A' has the coordinates ((a2c2+c1),(c2+c1a2)) Plug in the values given in your specific problem.
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