the ratio if john's money to Fred's money is 8:3.If john gives fred $6,john will have twice as much money as fred.How much money does john have before he gives fred money?

- anonymous

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- terenzreignz

This is kind of tricky, you know.

- anonymous

not for that smart brain of yours

- terenzreignz

My brain isn't smart. *I* am. ;)
HAHA
Kidding ^^
What's tricky is explaining it to you. Let me think of a way...

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## More answers

- anonymous

lol your funny

- anonymous

i need to hurry cause my mom is rushing me

- terenzreignz

This isn't something that we can solve in a hurry :>
Maybe you should rest now? :D

- anonymous

i cant cause im really busy and this is due tomorrow morning

- anonymous

isnt there something we can work out

- anonymous

can we finish this at 3:30

- terenzreignz

Well then, your mom's going to have to wait

- anonymous

lol yeah

- anonymous

ok lets start

- terenzreignz

Okay. I'll try and make this quick. But this is not how it should be done, okay? haha

- anonymous

okay

- terenzreignz

Suffice it to say, Fred only has 3/8 of John's money.
We're looking for how much John originally had.

- anonymous

yes

- terenzreignz

So. John's original amount is x
Fred's is 3/8 x

- anonymous

yes

- terenzreignz

Now if John gives Fred 6, his amount will become
x - 6
because he loses 6, right?
What happens to Fred's money?

- anonymous

he will gain 6

- terenzreignz

so his amount becomes...?

- anonymous

9

- terenzreignz

no. Where did you get that? haha
His amount was originally 3/8 x
so you just add 6 to that

- anonymous

6 3/8

- terenzreignz

\[\Large \frac38x + 6\]
more like :P

- terenzreignz

So John's new amount is x - 6
and that thing up there ^
is Fred's new amount
Apparently, with these new amounts, John has twice Fred's money.
So, in equations, that'd be
\[\Large x - 6 = 2\left[\frac38x + 6\right]\]

- terenzreignz

Now solve for x as you did last time

- anonymous

thats really confusing like last time lol

- terenzreignz

It's just the fraction.
But actually, you just distribute the 2 to the two terms inside the []
much like you did with the 6 earlier.

- anonymous

x-6=6/8+12

- anonymous

is that correct

- terenzreignz

It is.
You can multiply everything by 8 to get rid of that denominator.

- terenzreignz

And again, you missed a spot.
x's don't just disappear XD

- terenzreignz

\[\Large x - 6 = 2\left[\frac38\color{red}x + 6\right]\]

- anonymous

i still don't get it can you just tell me what x is

- anonymous

please friend

- anonymous

friends are suppose to help friends

- terenzreignz

I have a name, you know LOL

- anonymous

please help me terence

- anonymous

what is x suppose to be

- terenzreignz

lol that's just an alias I've been using.
I'll multiply by 8, you do the rest.
You CAN do it, because you did it before lol
8x - 48 = 6x + 96
Now solve it.

- anonymous

plus 48 to both sides

- anonymous

???????????

- terenzreignz

Yup.
You get...?

- anonymous

or minus 96 to both sides

- terenzreignz

Better to add 48 to both sides.

- anonymous

8x=6x+144

- anonymous

??

- terenzreignz

good. Next?

- anonymous

-6x to both sides

- terenzreignz

Okay. And you get...?

- anonymous

2x=144 which x equals 72 yes

- anonymous

!!!!!!!!!!!!!!

- terenzreignz

And that's the answer.
See? You CAN do it.
You don't need me to tell you the answer haha

- anonymous

lol

- anonymous

do you want your reward

- terenzreignz

new medal? haha
sure ^_^

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