## anonymous one year ago the ratio if john's money to Fred's money is 8:3.If john gives fred \$6,john will have twice as much money as fred.How much money does john have before he gives fred money?

• This Question is Open
1. terenzreignz

This is kind of tricky, you know.

2. anonymous

not for that smart brain of yours

3. terenzreignz

My brain isn't smart. *I* am. ;) HAHA Kidding ^^ What's tricky is explaining it to you. Let me think of a way...

4. anonymous

5. anonymous

i need to hurry cause my mom is rushing me

6. terenzreignz

This isn't something that we can solve in a hurry :> Maybe you should rest now? :D

7. anonymous

i cant cause im really busy and this is due tomorrow morning

8. anonymous

isnt there something we can work out

9. anonymous

can we finish this at 3:30

10. terenzreignz

Well then, your mom's going to have to wait

11. anonymous

lol yeah

12. anonymous

ok lets start

13. terenzreignz

Okay. I'll try and make this quick. But this is not how it should be done, okay? haha

14. anonymous

okay

15. terenzreignz

Suffice it to say, Fred only has 3/8 of John's money. We're looking for how much John originally had.

16. anonymous

yes

17. terenzreignz

So. John's original amount is x Fred's is 3/8 x

18. anonymous

yes

19. terenzreignz

Now if John gives Fred 6, his amount will become x - 6 because he loses 6, right? What happens to Fred's money?

20. anonymous

he will gain 6

21. terenzreignz

so his amount becomes...?

22. anonymous

9

23. terenzreignz

no. Where did you get that? haha His amount was originally 3/8 x so you just add 6 to that

24. anonymous

6 3/8

25. terenzreignz

$\Large \frac38x + 6$ more like :P

26. terenzreignz

So John's new amount is x - 6 and that thing up there ^ is Fred's new amount Apparently, with these new amounts, John has twice Fred's money. So, in equations, that'd be $\Large x - 6 = 2\left[\frac38x + 6\right]$

27. terenzreignz

Now solve for x as you did last time

28. anonymous

thats really confusing like last time lol

29. terenzreignz

It's just the fraction. But actually, you just distribute the 2 to the two terms inside the [] much like you did with the 6 earlier.

30. anonymous

x-6=6/8+12

31. anonymous

is that correct

32. terenzreignz

It is. You can multiply everything by 8 to get rid of that denominator.

33. terenzreignz

And again, you missed a spot. x's don't just disappear XD

34. terenzreignz

$\Large x - 6 = 2\left[\frac38\color{red}x + 6\right]$

35. anonymous

i still don't get it can you just tell me what x is

36. anonymous

37. anonymous

friends are suppose to help friends

38. terenzreignz

I have a name, you know LOL

39. anonymous

40. anonymous

what is x suppose to be

41. terenzreignz

lol that's just an alias I've been using. I'll multiply by 8, you do the rest. You CAN do it, because you did it before lol 8x - 48 = 6x + 96 Now solve it.

42. anonymous

plus 48 to both sides

43. anonymous

???????????

44. terenzreignz

Yup. You get...?

45. anonymous

or minus 96 to both sides

46. terenzreignz

Better to add 48 to both sides.

47. anonymous

8x=6x+144

48. anonymous

??

49. terenzreignz

good. Next?

50. anonymous

-6x to both sides

51. terenzreignz

Okay. And you get...?

52. anonymous

2x=144 which x equals 72 yes

53. anonymous

!!!!!!!!!!!!!!

54. terenzreignz

And that's the answer. See? You CAN do it. You don't need me to tell you the answer haha

55. anonymous

lol

56. anonymous