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anonymous
 one year ago
graph/ solve
anonymous
 one year ago
graph/ solve

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439060839044:dw

phi
 one year ago
Best ResponseYou've already chosen the best response.2we have negative numbers with a relation so *we have to be careful* the "fast way" is multiply both sides by 1 and *switch the relation operator* the slow (but easy to do) way is add +3 to both sides then add +3  x5 to both sides either way, what do you get?

phi
 one year ago
Best ResponseYou've already chosen the best response.2do it in steps 3  x5 < 3 which way do you want to do it? fast way or slow way?

phi
 one year ago
Best ResponseYou've already chosen the best response.2fast way: multiply both sides by 1 *flip the relation operator*

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0would it be 3/x5/<3 ??

phi
 one year ago
Best ResponseYou've already chosen the best response.2you did step 1 ok. but step 2 means you change < to > or if you had > you would change it to < or \(\le\) would be changed to \( \ge\) that is the "flip" part

phi
 one year ago
Best ResponseYou've already chosen the best response.2yes. the problem with the fast way is you have to remember to flip the operator... if you don't have a good memory for "details", the slow way is safer (one less rule to remember) so now you have 3  x5 > 3 it is safe to divide both sides by 3. you get  x5  > 1

phi
 one year ago
Best ResponseYou've already chosen the best response.2with absolute value problems we *always* have two conditions either x5 is positive , in which case , drop the   or x5 is negative, in which case we replace the   with 1*(x5)

phi
 one year ago
Best ResponseYou've already chosen the best response.2let's do the x5 is positive condition. we have x5 > 1 now add +5 to both sides

phi
 one year ago
Best ResponseYou've already chosen the best response.2now do the x5 is negative case. can you do that one?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes(hopefully)! So i got x<4

phi
 one year ago
Best ResponseYou've already chosen the best response.2looks good. x<4 or x>6 are the solutions put an open circle at 4. the open (not solid , filled in) means 4 is not part of the answer, but we can get as close to 4 as we want (without being exactly 4) and x smaller than 4. all numbers smaller (to the left) of 4 are part of the solution as it would take a long time to draw a line showing all of the numbers, we use an arrow tip to show the answer includes all numbers the arrow points towards.

phi
 one year ago
Best ResponseYou've already chosen the best response.2and then do the same for x> 6 open circle at 6 an arrow pointing which way ??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0gotcha:) So, the arrows will be pointing in opposite direction x>6 and x<4 the arrows is showing thee way it'll go:)

phi
 one year ago
Best ResponseYou've already chosen the best response.2yes. one last point: put the answers on the same number line

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0kk. Hold on...dw:1439061932632:dw

phi
 one year ago
Best ResponseYou've already chosen the best response.2yes. looks good. for your teacher, make sure the "tick mark" for the 4 is clearly marked (in your graph it is not clear which tick mark is the 4)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Will do:)! Thanks again phi<3<3
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