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anonymous

  • one year ago

Given f(x)=5x+5 and g(x)=6x+1 then what is f(g(−8)) ? Given f(x)=10x+8 and g(x)=1x+4 then what is (f+g)(3)) ? Given f(x)=3x+4 and g(x)=8x+1 then what is (f−g)(0)) ?

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  1. anonymous
    • one year ago
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    Given f(x)=5x+5 and g(x)=6x+1, then what is f(g(−8)) ? First, substitute -8 to g(x). \(g(x)=6x+1\rightarrow g(x)=6(-8)+1\). Solve for x.

  2. anonymous
    • one year ago
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    Tell me what x is, so can move to step two.

  3. anonymous
    • one year ago
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    x = -47

  4. anonymous
    • one year ago
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    Good! Now, we need to substitute g(x)=-47 to f(x)=5x+5. \[f(x)=5x+5\rightarrow f(g(-8))= 5(-47)+5\]

  5. anonymous
    • one year ago
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    Solve it and that's the answer. :)

  6. anonymous
    • one year ago
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    -230?

  7. anonymous
    • one year ago
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    Correct. :)

  8. anonymous
    • one year ago
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    Can you help me with the rest ?

  9. anonymous
    • one year ago
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    Given f(x)=10x+8 and g(x)=1x+4 then what is (f+g)(3)) ? this is 45? Given f(x)=3x+4 and g(x)=8x+1 then what is (f−g)(0)) ? this is -1?

  10. anonymous
    • one year ago
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    Given f(x)=10x+8 and g(x)=1x+4 then what is (f+g)(3)) ? Add f(x) and g(x) first.

  11. anonymous
    • one year ago
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    11x + 12

  12. anonymous
    • one year ago
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    Then substitute 3 to x.

  13. anonymous
    • one year ago
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    33 + 12 = 45

  14. anonymous
    • one year ago
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    Oh wait, is that your answer? 45?

  15. anonymous
    • one year ago
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    lol yes

  16. anonymous
    • one year ago
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    I didn't see it at first. :D Yes you're right! I'll check your other answer. :)

  17. anonymous
    • one year ago
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    -5x - 3 = -5(0) -3 = -3

  18. anonymous
    • one year ago
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    \[3x+4-8x-1\]

  19. anonymous
    • one year ago
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    \[-5x+3\] Substitute 0 to x.

  20. anonymous
    • one year ago
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    -5x - 3 = -5(0) -3 = -3

  21. anonymous
    • one year ago
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    Wrong. \(-5x+3\) Substitute 0 to x.

  22. anonymous
    • one year ago
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    no positive 3

  23. anonymous
    • one year ago
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    Yes.

  24. anonymous
    • one year ago
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    Thank you can you help me with something else .

  25. anonymous
    • one year ago
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    Just post another question and I'd be happy to help. :)

  26. anonymous
    • one year ago
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    okay . thanks . !!!

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