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anonymous

  • one year ago

How many grams of aluminum chloride must decompose to produce 78.3 milliliters of aluminum metal, if the density of aluminum is 2.70 g/mL? Show all steps of your calculation as well as the final answer. I dont think I have the right answer. Can someone please check my work?

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  1. anonymous
    • one year ago
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    Show me your work ;)

  2. Rushwr
    • one year ago
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    AlCl3(s)+6H2O(l)→[Al(H2O)6]3+(aq)+3Cl−(aq) This the reaction right? I'm not sure though ! But according to the question it says combustion. If AlCl3 is cumbusted it doesn't form Al metal right ?

  3. Rushwr
    • one year ago
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    @Bozhena

  4. anonymous
    • one year ago
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    Actually in Water is should be like this: AlCl3(s) + H2O(l) = Al(OH)3(s) + HCl(aq) While for the combustion Im not sure, but whan you rise the T very higt it will break the bond between Al and Cl, and you should get Al(l).

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