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help_people

  • one year ago

Please check if this is right???

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  1. help_people
    • one year ago
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    A bucket of paint has spilled on a tile floor. The paint flow can be expressed with the function r(t) = 3t, where t represents time in minutes and r represents how far the paint is spreading. The flowing paint is creating a circular pattern on the tile. The area of the pattern can be expressed as A(r) = πr2. Part A: Find the area of the circle of spilled paint as a function of time, or A[r(t)]. Show your work. Part B: How large is the area of spilled paint after 10 minutes? You may use 3.14 to approximate π in this problem.

  2. help_people
    • one year ago
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    Part A: You will plug in 3t to A(r) = pir^2 When you plug in the 3t you get: A[r(t)]= pi(3t)^2 =pi * (3t)^2 =pi * (3t * 3t) =28.274334t^2 ( I was just simplifying). Part B: 30 is r, because 30 is the radius after 10 minutes: π(30)2=900π = 900 x 3.14=2826

  3. help_people
    • one year ago
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    @hartnn @Elsa123

  4. hartnn
    • one year ago
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    part A, don't simplify, write \(9\pi t^2\) as the answer. part B, writing units would be better 2826 sq. units

  5. help_people
    • one year ago
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    it also says show your work for part a so what would i put and ok for part b

  6. hartnn
    • one year ago
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    you did show your work for part A properly, just keep the final answer as 9pi t^2 and instead of writing answer for part B as 2826 write 2826 sq. units

  7. hartnn
    • one year ago
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    Part B: 10 is r, because 10 is the radius after 10 minutes: 9π(10^2)=900π = 900 x 3.14=2826 sq units. ^^^

  8. help_people
    • one year ago
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    yes i saw :)

  9. hartnn
    • one year ago
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    wait

  10. help_people
    • one year ago
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    I'm here :)

  11. hartnn
    • one year ago
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    Part B: 10 is t, because we need area after 10 minutes: 9π(10^2)=900π = 900 x 3.14=2826 sq units. ------------------ t =10, 10 is actually time :P

  12. help_people
    • one year ago
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    Is this what you would like me to do with Part A? : Part A: You will plug in 3t to A(r) = pir^2 When you plug in the 3t you get: A[r(t)]= pi(3t)^2 =pi * (3t)^2 =pi * (3t * 3t) =9pit^2

  13. hartnn
    • one year ago
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    yep

  14. help_people
    • one year ago
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    ok so is 30 still radius or ?

  15. help_people
    • one year ago
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    (just out of curiosity)

  16. hartnn
    • one year ago
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    where did you get 30 from?? i don't even see 30 in the question :P

  17. hartnn
    • one year ago
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    but yes, 30 will be the radius after 10 minutes :)

  18. triciaal
    • one year ago
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    yes

  19. help_people
    • one year ago
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    I believe i multiplied 10 x 3 in 3(t) to get 30 and called it radius. To think about it that was stupid.

  20. triciaal
    • one year ago
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    @hartnn r(t) = 3t and 10 = 10 so r = 30

  21. hartnn
    • one year ago
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    yes, i agreed, r =30

  22. help_people
    • one year ago
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    Is this what you wanted me to do with part a: Part A: You will plug in 3t to A(r) = pir^2 When you plug in the 3t you get: A[r(t)]= pi(3t)^2 =pi * (3t)^2 =pi * (3t * 3t) =9pit^2

  23. hartnn
    • one year ago
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    yes, part A is perfect

  24. help_people
    • one year ago
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    wait so what about pt b?

  25. help_people
    • one year ago
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    Part B: 10 is t, because we need area after 10 minutes: 9π(10^2)=900π = 900 x 3.14=2826 So, the answer is 2826 sq. units.

  26. hartnn
    • one year ago
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    Part B: 10 is t, because we need area after 10 minutes: 9π(10^2)=900π = 900 x 3.14=2826 sq units. yesss

  27. help_people
    • one year ago
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    ok so everything is bueno?

  28. hartnn
    • one year ago
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    bueno? yes, everything is okay :)

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