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anonymous

  • one year ago

An object has a constant acceleration of 40 ft/sec2, an initial velocity of −20 ft/sec, and an initial position of 10 ft. Find the position function, s(t), describing the motion of the object. Please help ill give medal

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  1. nuttyliaczar
    • one year ago
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    Do you remember the general position function?

  2. anonymous
    • one year ago
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    d(t)= integral v(t)dt= double integral a(t)?

  3. nuttyliaczar
    • one year ago
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    That's true but it only helps if you know one of those equations. The position function is: \[x _{0}+(dx/dt)t+(1/2)(d ^{2}x/dt ^{2})t ^{2}\] Or as you probably like to remember it: \[x _{0}+vt+\frac{ at ^{2} }{ 2 }\]

  4. nuttyliaczar
    • one year ago
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    But do keep in mind what you said too. It saves you the trouble of blindly memorizing three equations, and so you only need one of them to get the other two.

  5. nuttyliaczar
    • one year ago
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    Do you know what to do now? Because from here you just need to plug it in

  6. anonymous
    • one year ago
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    Not sure what to plug in

  7. anonymous
    • one year ago
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    just confused on the steps on how to solve the problem

  8. nuttyliaczar
    • one year ago
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    x0 is the initial position. v is the initial velocity (in retrospect I forgot to write v0 to be consistent). a is the acceleration. And t is time.

  9. nuttyliaczar
    • one year ago
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    I think you just need to set up the equation and leave t as is

  10. anonymous
    • one year ago
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    oh ok thank you

  11. anonymous
    • one year ago
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    so what would s(t) be or look like?

  12. anonymous
    • one year ago
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    would it be 10+ (-20)=40(t)^2/2?

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