## anonymous one year ago An object has a constant acceleration of 40 ft/sec2, an initial velocity of −20 ft/sec, and an initial position of 10 ft. Find the position function, s(t), describing the motion of the object. Please help ill give medal

1. nuttyliaczar

Do you remember the general position function?

2. anonymous

d(t)= integral v(t)dt= double integral a(t)?

3. nuttyliaczar

That's true but it only helps if you know one of those equations. The position function is: $x _{0}+(dx/dt)t+(1/2)(d ^{2}x/dt ^{2})t ^{2}$ Or as you probably like to remember it: $x _{0}+vt+\frac{ at ^{2} }{ 2 }$

4. nuttyliaczar

But do keep in mind what you said too. It saves you the trouble of blindly memorizing three equations, and so you only need one of them to get the other two.

5. nuttyliaczar

Do you know what to do now? Because from here you just need to plug it in

6. anonymous

Not sure what to plug in

7. anonymous

just confused on the steps on how to solve the problem

8. nuttyliaczar

x0 is the initial position. v is the initial velocity (in retrospect I forgot to write v0 to be consistent). a is the acceleration. And t is time.

9. nuttyliaczar

I think you just need to set up the equation and leave t as is

10. anonymous

oh ok thank you

11. anonymous

so what would s(t) be or look like?

12. anonymous

would it be 10+ (-20)=40(t)^2/2?