A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
what is the radius of a circle with the equation x^2+y^2+2x+4y9=0
anonymous
 one year ago
what is the radius of a circle with the equation x^2+y^2+2x+4y9=0

This Question is Closed

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1standard form equation of the circle \[\huge\rm (xh)^2+(yk)^2=r^2\] where (h,k) is the center point and r =radius

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1so move the 9 to the right side

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do you know what a "perfect square trinomial" is? sometimes also just called a "perfect square"

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.0\(x^2+y^2+2x+4y9=0\\ x^2+y^2+2x+4y=9\\ x^2+2x+y^2+4y=9\\ (x+1)^21+y^2+4y=9\\ (x+1)^2+y^2+4y=10\) Now do something similar with the \(y^2+4y\).

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So I would get 3 for my answer correct?

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.0Now look at what @Nnesha said

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So my answer would be 6?

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.0\(x^2+y^2+2x+4y9=0\\ x^2+y^2+2x+4y=9\\ x^2+2x+y^2+4y=9\\ (x+1)^21+y^2+4y=9\\ (x+1)^2+y^2+4y=10\\ (x+1)^2+(y+2)^24=10\\ (x+1)^2+(y+2)^2=14\\ (x+1)^2+(y+2)^2=(\sqrt{14})^2\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So my answer should be 3.74 correct ?

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.0how did you get that?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.