Lilmike234
  • Lilmike234
what is the radius of a circle with the equation x^2+y^2+2x+4y-9=0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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Nnesha
  • Nnesha
standard form equation of the circle \[\huge\rm (x-h)^2+(y-k)^2=r^2\] where (h,k) is the center point and r =radius
Nnesha
  • Nnesha
so move the -9 to the right side
jdoe0001
  • jdoe0001
do you know what a "perfect square trinomial" is? sometimes also just called a "perfect square"

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Lilmike234
  • Lilmike234
Yeah I heard of it.
zzr0ck3r
  • zzr0ck3r
\(x^2+y^2+2x+4y-9=0\\ x^2+y^2+2x+4y=9\\ x^2+2x+y^2+4y=9\\ (x+1)^2-1+y^2+4y=9\\ (x+1)^2+y^2+4y=10\) Now do something similar with the \(y^2+4y\).
Lilmike234
  • Lilmike234
So I would get 3 for my answer correct?
zzr0ck3r
  • zzr0ck3r
Now look at what @Nnesha said
Lilmike234
  • Lilmike234
So my answer would be 6?
zzr0ck3r
  • zzr0ck3r
\(x^2+y^2+2x+4y-9=0\\ x^2+y^2+2x+4y=9\\ x^2+2x+y^2+4y=9\\ (x+1)^2-1+y^2+4y=9\\ (x+1)^2+y^2+4y=10\\ (x+1)^2+(y+2)^2-4=10\\ (x+1)^2+(y+2)^2=14\\ (x+1)^2+(y+2)^2=(\sqrt{14})^2\)
Lilmike234
  • Lilmike234
So my answer should be 3.74 correct ?
zzr0ck3r
  • zzr0ck3r
how did you get that?
Lilmike234
  • Lilmike234
I square rooted 14
zzr0ck3r
  • zzr0ck3r
right

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