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Lilmike234
 one year ago
what is the radius of a circle with the equation x^2+y^2+2x+4y9=0
Lilmike234
 one year ago
what is the radius of a circle with the equation x^2+y^2+2x+4y9=0

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Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1standard form equation of the circle \[\huge\rm (xh)^2+(yk)^2=r^2\] where (h,k) is the center point and r =radius

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1so move the 9 to the right side

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0do you know what a "perfect square trinomial" is? sometimes also just called a "perfect square"

lilmike234
 one year ago
Best ResponseYou've already chosen the best response.1Yeah I heard of it.

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.0\(x^2+y^2+2x+4y9=0\\ x^2+y^2+2x+4y=9\\ x^2+2x+y^2+4y=9\\ (x+1)^21+y^2+4y=9\\ (x+1)^2+y^2+4y=10\) Now do something similar with the \(y^2+4y\).

lilmike234
 one year ago
Best ResponseYou've already chosen the best response.1So I would get 3 for my answer correct?

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.0Now look at what @Nnesha said

lilmike234
 one year ago
Best ResponseYou've already chosen the best response.1So my answer would be 6?

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.0\(x^2+y^2+2x+4y9=0\\ x^2+y^2+2x+4y=9\\ x^2+2x+y^2+4y=9\\ (x+1)^21+y^2+4y=9\\ (x+1)^2+y^2+4y=10\\ (x+1)^2+(y+2)^24=10\\ (x+1)^2+(y+2)^2=14\\ (x+1)^2+(y+2)^2=(\sqrt{14})^2\)

lilmike234
 one year ago
Best ResponseYou've already chosen the best response.1So my answer should be 3.74 correct ?

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.0how did you get that?
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