## anonymous one year ago Draw the angle given in degrees on the unit circle where 0 radians corresponds to the positive portion of the horizontal axis: -16pi/7

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1. anonymous

anyone ?

2. anonymous

plz help me

3. anonymous

plz help me

4. anonymous

$$\bf \cfrac{16}{7}\implies \cfrac{7+7+2}{7}\implies \cfrac{\cancel{7}}{\cancel{7}}+\cfrac{\cancel{7}}{\cancel{7}}+\cfrac{2}{7}\implies 1+1+\cfrac{2}{7} \\ \quad \\ 2+\cfrac{2}{7} \\ \quad \\ thus\qquad -\cfrac{16}{7}\implies -2\pi -\cfrac{2\pi }{7}$$ notice, a full CLOCKWISE cycle is $$-2\pi$$ so just draw the remaining after the cycle and then get the CLOCKWISE angle

5. anonymous

shoot... actually that's backwards

6. anonymous

notice, a full CLOCKWISE cycle is −2π so just draw the remaining after the cycle and then get the COUNTER-CLOCKWISE angle

7. anonymous

anyhow $$\bf -\cfrac{16\pi }{7}\implies -2\pi -\cfrac{2\pi }{7}$$

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