sectheta - costheta / sintheta

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sectheta - costheta / sintheta

Mathematics
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write sec theta in terms of sin,cos sec theta = what ? do you know ?
yeS or n0 ?
no :)

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Other answers:

one would note there isn't really a questoin, just a statement
what does sec equal to ?
or in other words do you know the definition of sec theta ?
Write in terms of sin and cosine and simplify
did you read my comments ? I want to know how much you already know abt trig
^ :D
Not much at all am taking it this semester just trying to get a head start
thanks thank you!!! \[\rm \sin \theta = \frac{ 1 }{ \csc \theta }\]\[\cos \theta =\frac{ 1 }{ \sec \theta }\]\[\tan \theta=\frac{ 1 }{ \cot \theta } = \frac{ \sin \theta }{ \cos \theta }\] these are the definition of sin,cos and tan cos is reciprocal of sec
so you can replace sec with 1/cos \[\huge\rm \frac{ \color{reD}{\sec} \theta -\cos \theta }{ \sin \theta }\] \[\huge\rm \frac{ \frac{ 1 }{ \cos \theta } -\cos \theta }{ \sin \theta }\] now find the common denominator of \[\frac{ 1 }{ \cos \theta }-\cos \theta \]
Thanks
no done yet.
not*
can you solve that from there ?
Would be appreciated if you can finish it
well,hm common denominator is cos \[\frac{ \frac{ 1-\cos^ 2 \theta }{ \cos }}{ \sin \theta }\] so multiply both terms by cos 1/cos times cos and cos times cos when you multiply same bases you should add their exponents so cos times cos = cos^2 and 1/cos times cos =1 tthat's how you get 1 -cos^2 theta
now you must know this special identity \[\huge\rm sin^2 \theta+\cos^2 \theta =1\] solve this equation for sin^2 theta let me know what you get

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