anonymous one year ago sectheta - costheta / sintheta

1. Nnesha

write sec theta in terms of sin,cos sec theta = what ? do you know ?

2. Nnesha

yeS or n0 ?

3. imqwerty

no :)

4. jdoe0001

one would note there isn't really a questoin, just a statement

5. Nnesha

what does sec equal to ?

6. Nnesha

or in other words do you know the definition of sec theta ?

7. anonymous

Write in terms of sin and cosine and simplify

8. Nnesha

did you read my comments ? I want to know how much you already know abt trig

9. imqwerty

^ :D

10. anonymous

Not much at all am taking it this semester just trying to get a head start

11. Nnesha

thanks thank you!!! $\rm \sin \theta = \frac{ 1 }{ \csc \theta }$$\cos \theta =\frac{ 1 }{ \sec \theta }$$\tan \theta=\frac{ 1 }{ \cot \theta } = \frac{ \sin \theta }{ \cos \theta }$ these are the definition of sin,cos and tan cos is reciprocal of sec

12. Nnesha

so you can replace sec with 1/cos $\huge\rm \frac{ \color{reD}{\sec} \theta -\cos \theta }{ \sin \theta }$ $\huge\rm \frac{ \frac{ 1 }{ \cos \theta } -\cos \theta }{ \sin \theta }$ now find the common denominator of $\frac{ 1 }{ \cos \theta }-\cos \theta$

13. anonymous

Thanks

14. Nnesha

no done yet.

15. Nnesha

not*

16. Nnesha

can you solve that from there ?

17. anonymous

Would be appreciated if you can finish it

18. Nnesha

well,hm common denominator is cos $\frac{ \frac{ 1-\cos^ 2 \theta }{ \cos }}{ \sin \theta }$ so multiply both terms by cos 1/cos times cos and cos times cos when you multiply same bases you should add their exponents so cos times cos = cos^2 and 1/cos times cos =1 tthat's how you get 1 -cos^2 theta

19. Nnesha

now you must know this special identity $\huge\rm sin^2 \theta+\cos^2 \theta =1$ solve this equation for sin^2 theta let me know what you get