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anonymous
 one year ago
sectheta  costheta / sintheta
anonymous
 one year ago
sectheta  costheta / sintheta

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Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1write sec theta in terms of sin,cos sec theta = what ? do you know ?

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0one would note there isn't really a questoin, just a statement

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1what does sec equal to ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1or in other words do you know the definition of sec theta ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Write in terms of sin and cosine and simplify

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1did you read my comments ? I want to know how much you already know abt trig

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Not much at all am taking it this semester just trying to get a head start

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1thanks thank you!!! \[\rm \sin \theta = \frac{ 1 }{ \csc \theta }\]\[\cos \theta =\frac{ 1 }{ \sec \theta }\]\[\tan \theta=\frac{ 1 }{ \cot \theta } = \frac{ \sin \theta }{ \cos \theta }\] these are the definition of sin,cos and tan cos is reciprocal of sec

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1so you can replace sec with 1/cos \[\huge\rm \frac{ \color{reD}{\sec} \theta \cos \theta }{ \sin \theta }\] \[\huge\rm \frac{ \frac{ 1 }{ \cos \theta } \cos \theta }{ \sin \theta }\] now find the common denominator of \[\frac{ 1 }{ \cos \theta }\cos \theta \]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1can you solve that from there ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Would be appreciated if you can finish it

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1well,hm common denominator is cos \[\frac{ \frac{ 1\cos^ 2 \theta }{ \cos }}{ \sin \theta }\] so multiply both terms by cos 1/cos times cos and cos times cos when you multiply same bases you should add their exponents so cos times cos = cos^2 and 1/cos times cos =1 tthat's how you get 1 cos^2 theta

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1now you must know this special identity \[\huge\rm sin^2 \theta+\cos^2 \theta =1\] solve this equation for sin^2 theta let me know what you get
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