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anonymous

  • one year ago

A solution is made by dissolving 4.0 moles of sodium chloride (NaCl) in 2.05 kilograms of water. If the molal boiling point constant for water (Kb) is 0.51 °C/m, what would be the boiling point of this solution? Show all of the work needed to solve this problem

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  1. anonymous
    • one year ago
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    @Photon336 please help

  2. anonymous
    • one year ago
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    @abb0t

  3. taramgrant0543664
    • one year ago
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    So our first step is to determine how many moles of NaOH we have per kilogram of water m=4.0 moles/2.05kg m=?

  4. taramgrant0543664
    • one year ago
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    @lovingod786 ??

  5. anonymous
    • one year ago
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    Sorry Im here

  6. anonymous
    • one year ago
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    @taramgrant0543664

  7. anonymous
    • one year ago
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    1.95 kg?

  8. taramgrant0543664
    • one year ago
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    Yes it would be 1.95 but it would be moles/kg

  9. anonymous
    • one year ago
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    ok

  10. anonymous
    • one year ago
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    then what

  11. taramgrant0543664
    • one year ago
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    So our next step is to find our van't Hoff factor which is represented by i

  12. anonymous
    • one year ago
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    que? Mind speaking english lol

  13. taramgrant0543664
    • one year ago
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    This factor is a constant associated with the dissociation of the solute in the solvent

  14. taramgrant0543664
    • one year ago
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    So NaCl breaks down into two ions Na+ and Cl- meaning that our i value is 2 (keep in mind that it changes for each reaction)

  15. anonymous
    • one year ago
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    ok

  16. taramgrant0543664
    • one year ago
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    Last step now! We have a formula which is T=iKbm T is your change in temperature, i is 2 as found in second step, Kb is given 0.51 and m is what we found in the first step

  17. anonymous
    • one year ago
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    ok so T= (2)(0.51)(1.95) = 1.989 mol/kg yes?

  18. taramgrant0543664
    • one year ago
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    Yes so the change in temperature is 1.989 (note it's not in mol/kg anymore it is degrees celcius now) to find the boiling point you add this number to the boiling point of water

  19. anonymous
    • one year ago
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    so 1.989 + 0.51?

  20. taramgrant0543664
    • one year ago
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    The boiling point for water is 100 C so you would add that to the 1.989 the 0.51 is just a constant. For boiling point with water involved you add to 100. If you are doing freezing point with water then you would subtract from zero since 0 is the freezing point.

  21. anonymous
    • one year ago
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    so 109.989

  22. taramgrant0543664
    • one year ago
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    101.989 celcius would be the boiling point

  23. anonymous
    • one year ago
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    So thats the answer?

  24. taramgrant0543664
    • one year ago
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    Yes that would be your answer for the boiling point

  25. anonymous
    • one year ago
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    ok thx

  26. anonymous
    • one year ago
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    i got another question would you like to help

  27. taramgrant0543664
    • one year ago
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    Of course I can help, start a new post though so I can find everything easier please!

  28. anonymous
    • one year ago
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    ok

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