anonymous
  • anonymous
A solution is made by dissolving 4.0 moles of sodium chloride (NaCl) in 2.05 kilograms of water. If the molal boiling point constant for water (Kb) is 0.51 °C/m, what would be the boiling point of this solution? Show all of the work needed to solve this problem
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
@Photon336 please help
anonymous
  • anonymous
@abb0t
taramgrant0543664
  • taramgrant0543664
So our first step is to determine how many moles of NaOH we have per kilogram of water m=4.0 moles/2.05kg m=?

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taramgrant0543664
  • taramgrant0543664
@lovingod786 ??
anonymous
  • anonymous
Sorry Im here
anonymous
  • anonymous
@taramgrant0543664
anonymous
  • anonymous
1.95 kg?
taramgrant0543664
  • taramgrant0543664
Yes it would be 1.95 but it would be moles/kg
anonymous
  • anonymous
ok
anonymous
  • anonymous
then what
taramgrant0543664
  • taramgrant0543664
So our next step is to find our van't Hoff factor which is represented by i
anonymous
  • anonymous
que? Mind speaking english lol
taramgrant0543664
  • taramgrant0543664
This factor is a constant associated with the dissociation of the solute in the solvent
taramgrant0543664
  • taramgrant0543664
So NaCl breaks down into two ions Na+ and Cl- meaning that our i value is 2 (keep in mind that it changes for each reaction)
anonymous
  • anonymous
ok
taramgrant0543664
  • taramgrant0543664
Last step now! We have a formula which is T=iKbm T is your change in temperature, i is 2 as found in second step, Kb is given 0.51 and m is what we found in the first step
anonymous
  • anonymous
ok so T= (2)(0.51)(1.95) = 1.989 mol/kg yes?
taramgrant0543664
  • taramgrant0543664
Yes so the change in temperature is 1.989 (note it's not in mol/kg anymore it is degrees celcius now) to find the boiling point you add this number to the boiling point of water
anonymous
  • anonymous
so 1.989 + 0.51?
taramgrant0543664
  • taramgrant0543664
The boiling point for water is 100 C so you would add that to the 1.989 the 0.51 is just a constant. For boiling point with water involved you add to 100. If you are doing freezing point with water then you would subtract from zero since 0 is the freezing point.
anonymous
  • anonymous
so 109.989
taramgrant0543664
  • taramgrant0543664
101.989 celcius would be the boiling point
anonymous
  • anonymous
So thats the answer?
taramgrant0543664
  • taramgrant0543664
Yes that would be your answer for the boiling point
anonymous
  • anonymous
ok thx
anonymous
  • anonymous
i got another question would you like to help
taramgrant0543664
  • taramgrant0543664
Of course I can help, start a new post though so I can find everything easier please!
anonymous
  • anonymous
ok

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