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@Photon336 please help
So our first step is to determine how many moles of NaOH we have per kilogram of water m=4.0 moles/2.05kg m=?
Sorry Im here
Yes it would be 1.95 but it would be moles/kg
So our next step is to find our van't Hoff factor which is represented by i
que? Mind speaking english lol
This factor is a constant associated with the dissociation of the solute in the solvent
So NaCl breaks down into two ions Na+ and Cl- meaning that our i value is 2 (keep in mind that it changes for each reaction)
Last step now! We have a formula which is T=iKbm T is your change in temperature, i is 2 as found in second step, Kb is given 0.51 and m is what we found in the first step
ok so T= (2)(0.51)(1.95) = 1.989 mol/kg yes?
Yes so the change in temperature is 1.989 (note it's not in mol/kg anymore it is degrees celcius now) to find the boiling point you add this number to the boiling point of water
so 1.989 + 0.51?
The boiling point for water is 100 C so you would add that to the 1.989 the 0.51 is just a constant. For boiling point with water involved you add to 100. If you are doing freezing point with water then you would subtract from zero since 0 is the freezing point.
101.989 celcius would be the boiling point
So thats the answer?
Yes that would be your answer for the boiling point
i got another question would you like to help
Of course I can help, start a new post though so I can find everything easier please!