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help_people

  • one year ago

Which of the following functions has the largest value when x = 4? e(x) = x2 + 6x + 21 m(x) = 8x v(x) = 31x e(x) v(x) m(x) All the functions are equal at x = 4.

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  1. help_people
    • one year ago
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    c?

  2. help_people
    • one year ago
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    @triciaal

  3. Mehek14
    • one year ago
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    the only exponent is \(x^2\) right?

  4. help_people
    • one year ago
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    yes :)

  5. help_people
    • one year ago
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    8x is 8^x also 31x is 31(x)

  6. Mehek14
    • one year ago
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    \(x^2\\8^x\\31x\) like that?

  7. anonymous
    • one year ago
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    plug 4 in each of the functions and see which is the largest value

  8. help_people
    • one year ago
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    yes

  9. help_people
    • one year ago
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    i did i got c but I'm making sure

  10. Mehek14
    • one year ago
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    i'm asking if it's like this \(x^2\\8^x\\31x\)

  11. help_people
    • one year ago
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    yes it is @Mehek14 i already said that :)

  12. anonymous
    • one year ago
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    if this is what u mean e(x) = x^2 + 6x + 21 m(x) = 8^x v(x) = 31x then when we plug in 4 we get e(x)= 61 m(x)= 4096 v(x)= 124

  13. anonymous
    • one year ago
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    meaning m(x) is the highest value

  14. Mehek14
    • one year ago
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    C is correct

  15. help_people
    • one year ago
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    ok i thought so thank you everybody ! :)

  16. anonymous
    • one year ago
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    you're welcome :D

  17. triciaal
    • one year ago
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    yes C

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