anonymous
  • anonymous
what is the difference between moment of inertia and mass inertia (if there is )
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Hope this helps you. when inertia can act as athe mass ,force and generate momentu, the why another word called mass moment of inertia. how is it different from inertia.because the momemtum has been generated because of mass and velocity hence generates force.this is how the inertia behaves. even though why we use the terms called 'moment of inertia" & 'mass momet of inertia'. what is the exact difference between them Reference https://www.physicsforums.com/threads/what-tis-hte-difference-betweeen-mass-moment-of-inertia-and-inertia.102071/
IrishBoy123
  • IrishBoy123
2 bodies can have the same mass but a different geometry. in linear motion, that shouldn't matter. \( F = ma \) does not depend on the geometry. ordinary "mass" inertia is a term that describes the "unwillingness" of a body to change its velocity , ie direction or speed in linear motion. the moment of inertia is used when considering rotation of a body. 2 bodies of the same mass but different geometry will respond differently to an applied torque. the body that is more "spread out" will be more resistant to spinning because it has a greater moment of inertia. if you take a body of mass m and divide it into minuscule sub-masses, each of mass \(\delta m\), the moment of inertia of that body is \(\Sigma \ (\delta m_i \times r_i^2)\) where \(r_i\) is the distance of the small mass \(\delta m_i \) from the axis of rotation.

Looking for something else?

Not the answer you are looking for? Search for more explanations.