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anonymous
 one year ago
What is the center and radius of the circle (x+4)^2+(y2)^2=16
anonymous
 one year ago
What is the center and radius of the circle (x+4)^2+(y2)^2=16

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jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0Hint: Rewrite \[\Large (x+4)^2+(y2)^2=16\] as \[\Large (x(4))^2+(y2)^2=4^2\] and compare that to the general form\[\Large (xh)^2+(yk)^2=r^2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So the center is (4,2) and the radius is 16

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0for the r what is the square root of 16?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0yes... so our radius is actually 4. our center is in the form of (h,k). I think opposites signs are needed. I have to recheck this one fast one.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So the center is (4,2)

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0ah it's like solving for x and solving for y yeah(4,2) is the center... radius is 4

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0\[\Large (x({\color{red}{4}}))^2+(y{\color{blue}{2}})^2={\color{green}{4}}^2\] \[\Large (x{\color{red}{h}})^2+(y{\color{blue}{k}})^2={\color{green}{r}}^2\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0ok... it's (4,2) for center radius is 4 ... whew just double checking. I"m 75% sleepy
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