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caishaax3

  • one year ago

Multiply x^1/3 times x^3/7 .

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  1. Caishaax3
    • one year ago
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    do i need a common denominator?

  2. Caishaax3
    • one year ago
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    or do i just multiply them

  3. anonymous
    • one year ago
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    \[\frac{ x^1 }{ 3 } \times \frac{ x^3 }{ 7 }\] you just multiply it.

  4. jim_thompson5910
    • one year ago
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    Use this rule \[\LARGE x^{a} * x^{b} = x^{a+b}\] to get \[\LARGE x^{1/3} * x^{3/7} = x^{1/3+3/7} = ??\]

  5. jim_thompson5910
    • one year ago
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    to add 1/3 to 3/7, yes you will need a common denominator

  6. Caishaax3
    • one year ago
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    so it ends up x^3/21

  7. Caishaax3
    • one year ago
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    if i just multiply it

  8. anonymous
    • one year ago
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    \[x ^{a}\times x ^{b}=x ^{a+b}\]

  9. anonymous
    • one year ago
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    a=1 b=3

  10. anonymous
    • one year ago
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    try again

  11. Caishaax3
    • one year ago
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    x^1 times x^3 = x^4?

  12. anonymous
    • one year ago
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    yes

  13. Caishaax3
    • one year ago
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    now what ? @Shalante

  14. anonymous
    • one year ago
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    You thought the answer was x^3/21 earlier but it is x^4/21 The denominator you multiplied was correct, but your numerator was not. Now both are correct.

  15. UnkleRhaukus
    • one year ago
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    \[ x^{1/3}\times x^{3/7}=x^{1/3+3/7}=x^{7/21+9/21}=x^{(7+9)/21}\]

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