anonymous one year ago can some one help me?

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1. anonymous
2. anonymous

Prove: In an equilateral triangle the three medians are equal.

3. jim_thompson5910

what do you have so far?

4. anonymous

absolutely nothing ive been staring at the page for an hour

5. jim_thompson5910

|dw:1439083430829:dw|

6. jim_thompson5910

|dw:1439083442888:dw|

7. jim_thompson5910

|dw:1439083487262:dw|

8. jim_thompson5910

do you see how P is the midpoint of AB?

9. anonymous

yes

10. jim_thompson5910

they use the midpoint formula to find point P

11. jim_thompson5910

that means you add up the x coordinates and divide by 2 |dw:1439083618310:dw|

12. jim_thompson5910

make sense?

13. anonymous

somewhat

14. jim_thompson5910

I added the x coordinates 0 and 2a to get 2a then I divided 2a by 2 to get 'a'

15. jim_thompson5910

|dw:1439083746502:dw|

16. anonymous

ok got it

17. jim_thompson5910

the same happens with the y coordinates |dw:1439083780104:dw|

18. anonymous

ok

19. jim_thompson5910

|dw:1439083807218:dw|

20. jim_thompson5910

so hopefully you see how (a,0) was found

21. anonymous

ya think so

22. jim_thompson5910

the same idea is applied to find Q and R

23. UsukiDoll

feels like a proof... like verify (a,0) using A and B

24. anonymous

okay

25. anonymous

i think i understand.. thanks

26. UsukiDoll

|dw:1439083816461:dw|

27. jim_thompson5910

for the other stuff, you use the distance formula $\Large d = \sqrt{\left(x_{2}-x_{1}\right)^2+\left(y_{2}-y_{1}\right)^2}$

28. anonymous

kk

29. anonymous

|dw:1439083949599:dw|

30. UsukiDoll

???

31. UsukiDoll

this assignment looks painful D: but I sort of see where they are going.

32. anonymous

it is very painful i have 7 more

33. UsukiDoll

clicked close by accident.

34. UsukiDoll

so we need Q and R hmmm Q is (3a/2,b/2) R is (a/2, b/2)

35. anonymous

lol i wish. It only lets me do that for quixs and test

36. UsukiDoll

no I said I accidentally closed the tab on my end XD

37. anonymous

ohhhhh lol

38. UsukiDoll

so I couldn't reach you for a bit XD

39. UsukiDoll

if Q ( 3a/2, b/2) then there are points that can lead us to this. if R ( a/2,b/2) then there are points that lead to this result points A and C may lead us to R

40. UsukiDoll

A (0,0) C (a,b) |dw:1439084550670:dw|

41. anonymous

okay

42. UsukiDoll

|dw:1439084709293:dw|

43. UsukiDoll

a HA! B AND C can make Q!

44. UsukiDoll

B(2a,0) C( a,b) (2a+a/2, 0+b/2) Q(3a/2,b/2)

45. UsukiDoll

|dw:1439084868914:dw|

46. UsukiDoll

|dw:1439084931274:dw|

47. anonymous

ohh!!! i understand now thank you sooo much!!!!

48. UsukiDoll

I think midpoint formula and distance formula is bring used here.

49. UsukiDoll

QA hmm Q(3a/2, b/2) A (0,0)

50. UsukiDoll

|dw:1439085179111:dw|

51. UsukiDoll

$\Large d = \sqrt{\left(x_{2}-x_{1}\right)^2+\left(y_{2}-y_{1}\right)^2}$ $\Large d = \sqrt{(0-\frac{3a}{2})^2+(0-\frac{b}{2})^2}$ $\Large d = \sqrt{(-\frac{3a}{2})^2+(-\frac{b}{2})^2}$ $\Large d = \sqrt{(\frac{9a^2}{4})+\frac{b^2}{4}}$ if we let $\large b = a \sqrt{3}$ $\Large d = \sqrt{(\frac{9a^2}{4})+\frac{(a \sqrt{3})^2}{4}}$ $\Large d = \sqrt{(\frac{9a^2}{4})+\frac{(3a^2)}{4}}$ $\Large d = \sqrt{\frac{12a^2}{4}}$ $\Large d = \sqrt{3a^2}$ $\Large d = a\sqrt{3}$ Now do the same process for RB for R ( a/2,b/2) and B (2a,0)