anonymous
  • anonymous
Expand the logarithmic expression. log7(n/5)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Nnesha
  • Nnesha
quotient rule\[\large\rm log_b y - \log_b x = \log_b \frac{ x }{ y}\] to condense you can change subtraction to division product rule \[\large\rm log_b x + \log_b y = \log_b( x \times y )\] addition ----> multiplication power rule \[\large\rm log_b x^y = y \log_b x\]
Nnesha
  • Nnesha
\[\huge\rm log_7 \frac{ n }{ 5}\]which property you should apply ?
anonymous
  • anonymous
quotient rule

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UsukiDoll
  • UsukiDoll
yes!
Nnesha
  • Nnesha
yep right btw 7 is base right ?
anonymous
  • anonymous
yes 7 is the base
Nnesha
  • Nnesha
alright
Nnesha
  • Nnesha
so how would you expand that ?
anonymous
  • anonymous
log7(5)-log5(n)
Nnesha
  • Nnesha
hmm log5(n) ??
anonymous
  • anonymous
oh, i meant 7
UsukiDoll
  • UsukiDoll
we need to have the same base value... 99% sure that's a typo
Nnesha
  • Nnesha
right :=)
anonymous
  • anonymous
it was a typo, thanks to both of you!
Nnesha
  • Nnesha
pleasure.
UsukiDoll
  • UsukiDoll
I think it's backwards though. with the quotient rule wouldn't it be \[\log_7(n)-\log_7(5)\]
anonymous
  • anonymous
are you sure? 5 was the denominator
Nnesha
  • Nnesha
ohh yeah i thought n is the denominator
UsukiDoll
  • UsukiDoll
-_- I saw log7(5)-log7(n) that's 5/n not n/5
Nnesha
  • Nnesha
nvm arnv my bad i typed that wrong in the properties
anonymous
  • anonymous
oh, don't worry about it, thank you guys again!
Nnesha
  • Nnesha
thanks! i'll write it correctly
Nnesha
  • Nnesha
\(\color{blue}{\text{Originally Posted by}}\) @Nnesha quotient rule\[\large\rm log_b y - \log_b x = \log_b \frac{ x }{ y}\] to condense you can change subtraction to division product rule \[\large\rm log_b x + \log_b y = \log_b( x \times y )\] addition ----> multiplication power rule \[\large\rm log_b x^y = y \log_b x\] \(\color{blue}{\text{End of Quote}}\) correction quotient rule\[\large\rm log_b x - \log_b y = \log_b \frac{ x }{ y}\] to condense you can change subtraction to division product rule \[\large\rm log_b x + \log_b y = \log_b( x \times y )\] addition ----> multiplication power rule \[\large\rm log_b x^y = y \log_b x\]
Nnesha
  • Nnesha
looks right ;)

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