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anonymous

  • one year ago

Expand the logarithmic expression. log7(n/5)

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  1. Nnesha
    • one year ago
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    quotient rule\[\large\rm log_b y - \log_b x = \log_b \frac{ x }{ y}\] to condense you can change subtraction to division product rule \[\large\rm log_b x + \log_b y = \log_b( x \times y )\] addition ----> multiplication power rule \[\large\rm log_b x^y = y \log_b x\]

  2. Nnesha
    • one year ago
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    \[\huge\rm log_7 \frac{ n }{ 5}\]which property you should apply ?

  3. anonymous
    • one year ago
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    quotient rule

  4. UsukiDoll
    • one year ago
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    yes!

  5. Nnesha
    • one year ago
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    yep right btw 7 is base right ?

  6. anonymous
    • one year ago
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    yes 7 is the base

  7. Nnesha
    • one year ago
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    alright

  8. Nnesha
    • one year ago
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    so how would you expand that ?

  9. anonymous
    • one year ago
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    log7(5)-log5(n)

  10. Nnesha
    • one year ago
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    hmm log5(n) ??

  11. anonymous
    • one year ago
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    oh, i meant 7

  12. UsukiDoll
    • one year ago
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    we need to have the same base value... 99% sure that's a typo

  13. Nnesha
    • one year ago
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    right :=)

  14. anonymous
    • one year ago
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    it was a typo, thanks to both of you!

  15. Nnesha
    • one year ago
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    pleasure.

  16. UsukiDoll
    • one year ago
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    I think it's backwards though. with the quotient rule wouldn't it be \[\log_7(n)-\log_7(5)\]

  17. anonymous
    • one year ago
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    are you sure? 5 was the denominator

  18. Nnesha
    • one year ago
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    ohh yeah i thought n is the denominator

  19. UsukiDoll
    • one year ago
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    -_- I saw log7(5)-log7(n) that's 5/n not n/5

  20. Nnesha
    • one year ago
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    nvm arnv my bad i typed that wrong in the properties

  21. anonymous
    • one year ago
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    oh, don't worry about it, thank you guys again!

  22. Nnesha
    • one year ago
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    thanks! i'll write it correctly

  23. Nnesha
    • one year ago
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    \(\color{blue}{\text{Originally Posted by}}\) @Nnesha quotient rule\[\large\rm log_b y - \log_b x = \log_b \frac{ x }{ y}\] to condense you can change subtraction to division product rule \[\large\rm log_b x + \log_b y = \log_b( x \times y )\] addition ----> multiplication power rule \[\large\rm log_b x^y = y \log_b x\] \(\color{blue}{\text{End of Quote}}\) correction quotient rule\[\large\rm log_b x - \log_b y = \log_b \frac{ x }{ y}\] to condense you can change subtraction to division product rule \[\large\rm log_b x + \log_b y = \log_b( x \times y )\] addition ----> multiplication power rule \[\large\rm log_b x^y = y \log_b x\]

  24. Nnesha
    • one year ago
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    looks right ;)

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