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|dw:1439090251436:dw|

look up the derivative of \(\sin^{-1}x\)

substitute \(u=\sin^{-1}x\)
then \(du=?\)

I'm confused on how you got U to be sin-1x, how did you know it was that?

I thought U was supposed what's inside roots or paretheses, such as 1-x^2

do you know what the derivative of \(\sin^{-1}x\) is ?

Yea...it's 1/srt 1-x^2 * dx

|dw:1439090695448:dw|

I get that!

okay thanks!

Also, don't forget to change the bounds accordingly

|dw:1439090839359:dw|

Why would I need to change the bounds?

|dw:1439090975245:dw|

those bounds refer to \(x\),
they don't belong to \(u\)

|dw:1439091066367:dw|

|dw:1439091093678:dw|

no wait, whats the integrand right after substituting ?

|dw:1439091171917:dw|

Yes, whats antiderivative of \(u\) with respective to \(u\) ?

U(x)?

nope, whats antiderivative of \(x\) with respect to \(x\) ?

ohh....so would it be U^2/2

Yes

but isnt U supposed to be thought of a constant, therefore it's antiderivative should be U of x?

\(u\) is not constant, it is the variable that has replaced \(\sin^{-1}x\)

|dw:1439091490507:dw|

Looks good!

So do I get a decimal answer when I evaluate the integral?

plugin the bounds and see

Okay so I got (sin-1(1/2))^2/2? So do I box in that as the answer or its decimal...which is .137077

recall that \(\sin(\pi/6)=1/2\)

look at the directions in the question

The directions in the questions just say evaluate the integral.

if it asks for EXACT answers which most professors want then you give them that

answer should be pi/6

ganeshie, is the answer (pi/6)^2/2?

my bad pi/12

wow i'm terrible today

hmm i got 5/2pi

haha thats not it

lol i need help then..

the answer i gave is wrong it should be pi/72 i'll show simplification right now one sec.

nope thats still wrong

ah i got it pi^2/72

looks good! :)

Yes thats what I got too saseal!

|dw:1439091910076:dw|

i meant to say pi^2/72 originally

yes leave it as \(\dfrac{\pi^2}{72}\)
do not convert to decimals unless asked to do so

Okay, cool, thanks ganeshie!

Thanks Ac3!