anonymous
  • anonymous
Can someone please help me finish this pre-calc question??? Express the complex number in trigonometric form. 2 - 2i This is what I have so far: r=absolute value(2-2i) r= sqrt((2)^2+(-2)^2) r=sqrt(8) r=2sqrt(2) theta(ref)=tan^-1*absolute value(2/-2) theta(ref)=pi/2 I dont know how to get the value of theta alone to complete this problem. What do i do next? Please help!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
\[2-2i\]\[r=\sqrt{2^2+(-2)^2}\]\[\tan^{-1} = (\frac{ -2 }{ 2 } ) = ?\]
anonymous
  • anonymous
you arent suppose to use radian mode for polar form
anonymous
  • anonymous
thats why you got pi/2

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anonymous
  • anonymous
I thought \[\tan^{-1} =\frac{ a }{ b }\]
anonymous
  • anonymous
no its b/a
anonymous
  • anonymous
|dw:1439092982007:dw|
anonymous
  • anonymous
better if i draw it out?
anonymous
  • anonymous
Yes. After switching it to b/a i got theta(ref)=-1
anonymous
  • anonymous
find out whats tan^1(-1)
anonymous
  • anonymous
tan^1(-1) or tan^-1(1)? tan^1(-1) is -1.55 or -tan(1) http://www.wolframalpha.com/input/?i=tan%5E1%28-1%29
anonymous
  • anonymous
\[\tan^{-1} (-1)\]
anonymous
  • anonymous
Okay, yeah tan^-1(-1) is -pi/4 or -45 degrees
anonymous
  • anonymous
now put that in 360 degrees form
anonymous
  • anonymous
find the angle that is coterminal to -45 degrees? Thats 315, right?
anonymous
  • anonymous
yea
anonymous
  • anonymous
you know how to make the polar form from there right?
anonymous
  • anonymous
oh wait its trigo form
anonymous
  • anonymous
Yea. I was stuck at theta(ref)= -1. I dont know what to do next
anonymous
  • anonymous
ok great you have the angles now you can form whatever it is
anonymous
  • anonymous
you should get \(\theta\) instantly from your eyeballs

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