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anonymous
 one year ago
What is the equation of the ellipse with covertices (0, 2), (0, 2) and vertices (3, 0), (3, 0)?
Please help? I have nO IDEA how to do this!
anonymous
 one year ago
What is the equation of the ellipse with covertices (0, 2), (0, 2) and vertices (3, 0), (3, 0)? Please help? I have nO IDEA how to do this!

This Question is Closed

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1hmmm, lets draw a graph, and plot those points

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1dw:1439094439604:dw

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1dw:1439094488079:dw can you do the others?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1(click on the yellow pencil icon, to reuse a drawing )

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439094586269:dw is this correct?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1whoops, i plotted that first point wrong,

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1(my mistake) dw:1439094795562:dw

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1[that's better now (sorry about that)] now we have the covertices plotted, we can draw the ellipse , so that is goes through these points . . .

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1(can you draw the ellipse?)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439094980170:dw

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1Good. dw:1439095016485:dw

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1Can you tell from the diagram now, where the centre of ellipse is ? and its semimajor axes?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1good, yes that is the centre

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1And remember that the axes are half the width (a), and half the height (b)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it's 6, and 4, right?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1the major axes (full width/height) are 6 and 4 we want the semimajor axes ... half these

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1you now have \((h,k)=(0,0)\) \(a=3\), \(b =2\) so plug these into \[\frac{(xh)^2}{a^2}+\frac{(yk)^2}{b^2} = 1\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(dw:1439095772471:dw

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1very good, now just simplify

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439095814555:dw

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1dw:1439095846244:dw

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1Great work! you're done

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you once again! :)
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