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anonymous

  • one year ago

here, a question .please help

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  1. anonymous
    • one year ago
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    let V be the space of polynomial over R \[\le2\]

  2. anonymous
    • one year ago
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    .let \[\emptyset _{1} \emptyset _{2} \emptyset _{3}\] be the linear functional on V defiend by

  3. anonymous
    • one year ago
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    \[\emptyset _{1}(f(t))=f(t)dt,\emptyset _{2}f(t)=f \prime (1),\emptyset _{3}(f(t))=f(0). here f(t)=a+bt+ct^2\] and f'(t) denots the derivative of f(t).

  4. anonymous
    • one year ago
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    find the basis {\[f _{1}(t),f _{2}(t),f _{3}(t)\] of V that is dual to \[ \emptyset _{1}, \emptyset _{2}, \emptyset _{3},\]

  5. anonymous
    • one year ago
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    please help

  6. anonymous
    • one year ago
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    @zzr0ck3r

  7. anonymous
    • one year ago
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    @oldrin.bataku

  8. anonymous
    • one year ago
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    @Loser66

  9. anonymous
    • one year ago
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    @Michele_Laino

  10. anonymous
    • one year ago
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    @Kainui

  11. anonymous
    • one year ago
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    @oldrin.bataku

  12. zzr0ck3r
    • one year ago
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    Can you tell me what a basis, functional, and what do you mean by spaces, and over R. If you ant answer all four of those questions, you should read up before trying this.

  13. anonymous
    • one year ago
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    @jtvatsim

  14. jtvatsim
    • one year ago
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    OK, so I noticed that zzr0ck3r had some questions for you. Were you clear on those definitions?

  15. jtvatsim
    • one year ago
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    Phew... that was tough. I hope it isn't so tough reading it. Take your time through it. Ultimately, dual just means that you will be setting equations equal to 0s and 1. It's a simple idea, but very hard to get across. Good luck! I'm signing off for tonight. :)

  16. jtvatsim
    • one year ago
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    Not sure if the attachment went through, here is is again.

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