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anonymous
 one year ago
here, a question .please help
anonymous
 one year ago
here, a question .please help

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0let V be the space of polynomial over R \[\le2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0.let \[\emptyset _{1} \emptyset _{2} \emptyset _{3}\] be the linear functional on V defiend by

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\emptyset _{1}(f(t))=f(t)dt,\emptyset _{2}f(t)=f \prime (1),\emptyset _{3}(f(t))=f(0). here f(t)=a+bt+ct^2\] and f'(t) denots the derivative of f(t).

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0find the basis {\[f _{1}(t),f _{2}(t),f _{3}(t)\] of V that is dual to \[ \emptyset _{1}, \emptyset _{2}, \emptyset _{3},\]

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.0Can you tell me what a basis, functional, and what do you mean by spaces, and over R. If you ant answer all four of those questions, you should read up before trying this.

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.0OK, so I noticed that zzr0ck3r had some questions for you. Were you clear on those definitions?

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.0Phew... that was tough. I hope it isn't so tough reading it. Take your time through it. Ultimately, dual just means that you will be setting equations equal to 0s and 1. It's a simple idea, but very hard to get across. Good luck! I'm signing off for tonight. :)

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.0Not sure if the attachment went through, here is is again.
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