Photon336
  • Photon336
Question
Chemistry
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Photon336
  • Photon336
388/389
1 Attachment
Photon336
  • Photon336
386/387
1 Attachment
Photon336
  • Photon336
@taramgrant0543664 @Rushwr @sweetburger @Woodward

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Photon336
  • Photon336
388 @rushwr?
Rushwr
  • Rushwr
thinking
Photon336
  • Photon336
\[Ca _{s} + Cl _{2g} \rightarrow CaCl _{2s}\]
Rushwr
  • Rushwr
is it B?
Rushwr
  • Rushwr
cuz the reaction is a formation reaction hence it is an exothermic reaction. SO delta H is negative
Rushwr
  • Rushwr
\[\Delta S _{surr} =\frac{ -\Delta H }{ T }\]
Photon336
  • Photon336
\[\Delta G = \Delta H - T \Delta S \] so for our reaction the entropy would have to go down. so the sign TDeltaS would be positive. that means that for our reaction, which we know is spontaneous because we form our reactants. Delta G < 0 if we put the two together. 1. Delta G <0 2. Entropy Delta S < 0 3. TdeltaS > 0 THIS means that T delta S would be > 0 positive. and Delta G < 0 therefore the enthalpy Delta H would have to be large and negative, to offset the positive entropy and that would make delta G < 0
Photon336
  • Photon336
sorry form our products***
Rushwr
  • Rushwr
389. A Cuz when they had more reactants in to the system the system tend to attain the equilibrium by making more products. So the euilibrium points shifts to the left forming more products.
Photon336
  • Photon336
\[\Delta G = \Delta H - T \Delta S \] True entropy is \[\Delta S = \frac{ -\Delta H }{ T }\] because we end up with solid calcium chloride (s) we know overall the entropy goes down. so in that equation. delta S < 0 \[\Delta S < 0 \] \[\Delta H < 0 \]
Photon336
  • Photon336
389 is so tricky the first time I did it i got it wrong
Photon336
  • Photon336
@taramgrant0543664 thoughts for 389?
Rushwr
  • Rushwr
what's the answer given for 389. I explained one !
taramgrant0543664
  • taramgrant0543664
So I was thinking at first A until I saw that it was in solid form solids don't change rate so I was considering c
Photon336
  • Photon336
@Rushwr it's C no change
Rushwr
  • Rushwr
oh yes it doesn't count for the K values yes. u are right!
Photon336
  • Photon336
equilibrium expressions, the K value(s) i think it's pure liquids and solids aren't included.
Rushwr
  • Rushwr
I didn't see the states properly ! Thank you @taramgrant0543664 and @Photon336
taramgrant0543664
  • taramgrant0543664
For it to be counted it's either in gas or aqueous form
Rushwr
  • Rushwr
@taramgrant0543664 I love you!
taramgrant0543664
  • taramgrant0543664
Definitely watch those states that's the thing that always gets me lol
Photon336
  • Photon336
\[Keq = [Cl _{2}] \] \[K _{eq} = \frac{ [C][D] }{ [A][B] }\]
Photon336
  • Photon336
yeah... that one got me too..
taramgrant0543664
  • taramgrant0543664
Was the answer for 388 said? I might have missed that I know I missed part of your conversation since I got tagged in the math section
Photon336
  • Photon336
it remains the same because the Keq depends only on the concentration of the gas chlorine.
Photon336
  • Photon336
so it's C
taramgrant0543664
  • taramgrant0543664
Right I was thinking that but thought I would double check as sometimes I am completely off on them lol what's the next one?
Photon336
  • Photon336
387. A. because like replacing a strong acid with a weak one in that reaction would cause the temperature change to rise to a smaller degree, and the enthalpy change would be less.
Photon336
  • Photon336
I just gave an answer for 387, so all that's left is 386
Photon336
  • Photon336
I will post one more set of questions then I g2g
Rushwr
  • Rushwr
okai !
Rushwr
  • Rushwr
Btw Thanks alot @Photon336
Photon336
  • Photon336
386 I missed that one
taramgrant0543664
  • taramgrant0543664
These are kind of fun to do @Photon336!! As for 386 I was considering D as my option possibly?
Rushwr
  • Rushwr
IKR this is awesome ! @taramgrant0543664 @Photon336
Photon336
  • Photon336
Yeah it's D.
Photon336
  • Photon336
ok Will post one more.

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