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Photon336

  • one year ago

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  1. Photon336
    • one year ago
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    388/389

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  2. Photon336
    • one year ago
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    386/387

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  3. Photon336
    • one year ago
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    @taramgrant0543664 @Rushwr @sweetburger @Woodward

  4. Photon336
    • one year ago
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    388 @rushwr?

  5. Rushwr
    • one year ago
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    thinking

  6. Photon336
    • one year ago
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    \[Ca _{s} + Cl _{2g} \rightarrow CaCl _{2s}\]

  7. Rushwr
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    is it B?

  8. Rushwr
    • one year ago
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    cuz the reaction is a formation reaction hence it is an exothermic reaction. SO delta H is negative

  9. Rushwr
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    \[\Delta S _{surr} =\frac{ -\Delta H }{ T }\]

  10. Photon336
    • one year ago
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    \[\Delta G = \Delta H - T \Delta S \] so for our reaction the entropy would have to go down. so the sign TDeltaS would be positive. that means that for our reaction, which we know is spontaneous because we form our reactants. Delta G < 0 if we put the two together. 1. Delta G <0 2. Entropy Delta S < 0 3. TdeltaS > 0 THIS means that T delta S would be > 0 positive. and Delta G < 0 therefore the enthalpy Delta H would have to be large and negative, to offset the positive entropy and that would make delta G < 0

  11. Photon336
    • one year ago
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    sorry form our products***

  12. Rushwr
    • one year ago
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    389. A Cuz when they had more reactants in to the system the system tend to attain the equilibrium by making more products. So the euilibrium points shifts to the left forming more products.

  13. Photon336
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    \[\Delta G = \Delta H - T \Delta S \] True entropy is \[\Delta S = \frac{ -\Delta H }{ T }\] because we end up with solid calcium chloride (s) we know overall the entropy goes down. so in that equation. delta S < 0 \[\Delta S < 0 \] \[\Delta H < 0 \]

  14. Photon336
    • one year ago
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    389 is so tricky the first time I did it i got it wrong

  15. Photon336
    • one year ago
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    @taramgrant0543664 thoughts for 389?

  16. Rushwr
    • one year ago
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    what's the answer given for 389. I explained one !

  17. taramgrant0543664
    • one year ago
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    So I was thinking at first A until I saw that it was in solid form solids don't change rate so I was considering c

  18. Photon336
    • one year ago
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    @Rushwr it's C no change

  19. Rushwr
    • one year ago
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    oh yes it doesn't count for the K values yes. u are right!

  20. Photon336
    • one year ago
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    equilibrium expressions, the K value(s) i think it's pure liquids and solids aren't included.

  21. Rushwr
    • one year ago
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    I didn't see the states properly ! Thank you @taramgrant0543664 and @Photon336

  22. taramgrant0543664
    • one year ago
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    For it to be counted it's either in gas or aqueous form

  23. Rushwr
    • one year ago
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    @taramgrant0543664 I love you!

  24. taramgrant0543664
    • one year ago
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    Definitely watch those states that's the thing that always gets me lol

  25. Photon336
    • one year ago
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    \[Keq = [Cl _{2}] \] \[K _{eq} = \frac{ [C][D] }{ [A][B] }\]

  26. Photon336
    • one year ago
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    yeah... that one got me too..

  27. taramgrant0543664
    • one year ago
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    Was the answer for 388 said? I might have missed that I know I missed part of your conversation since I got tagged in the math section

  28. Photon336
    • one year ago
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    it remains the same because the Keq depends only on the concentration of the gas chlorine.

  29. Photon336
    • one year ago
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    so it's C

  30. taramgrant0543664
    • one year ago
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    Right I was thinking that but thought I would double check as sometimes I am completely off on them lol what's the next one?

  31. Photon336
    • one year ago
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    387. A. because like replacing a strong acid with a weak one in that reaction would cause the temperature change to rise to a smaller degree, and the enthalpy change would be less.

  32. Photon336
    • one year ago
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    I just gave an answer for 387, so all that's left is 386

  33. Photon336
    • one year ago
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    I will post one more set of questions then I g2g

  34. Rushwr
    • one year ago
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    okai !

  35. Rushwr
    • one year ago
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    Btw Thanks alot @Photon336

  36. Photon336
    • one year ago
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    386 I missed that one

  37. taramgrant0543664
    • one year ago
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    These are kind of fun to do @Photon336!! As for 386 I was considering D as my option possibly?

  38. Rushwr
    • one year ago
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    IKR this is awesome ! @taramgrant0543664 @Photon336

  39. Photon336
    • one year ago
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    Yeah it's D.

  40. Photon336
    • one year ago
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    ok Will post one more.

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