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anonymous
 one year ago
From the top of a cliff,60 metres high, the angles of depression of the top and bottom of a tower are observed to be 30 ° and 60 °.Find the height of the tower.
anonymous
 one year ago
From the top of a cliff,60 metres high, the angles of depression of the top and bottom of a tower are observed to be 30 ° and 60 °.Find the height of the tower.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I can't understand..

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.3\[\tan\theta = \frac{\text{opp}}{\text{adj}}\]

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0Let AB be the building h meters high, and PQ be the tower 60 m high situated at distance BQ = x meters away. Then AC = BQ = x, CQ = AB = h, PC = 60 h From BPQ, cot 60° = BQ/PQ = x/60 => x = 60 cot 60° From APC, cot 30° = AC/PC = x/(60 h) => 60 h = x/ cot 30° = 60 cot 60° tan 30° = 60 (1/3)(1/3) = 20 => h = 60 20 = 40 Thus the building is 40 meters high and is situated 34·64 meters away from the tower.

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0i've given you the figure pls refer to it

sepeario
 one year ago
Best ResponseYou've already chosen the best response.0^^^^ i think the use of inverse trigonometric functions is unnecessary.

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0no by cot theta it is helpful and cot theta is just the opposite of tan theta

sepeario
 one year ago
Best ResponseYou've already chosen the best response.0Yes, but I don't think this person has actually learnt inverse trigonometry, and for the sake of simplicity I don't think he/she needs to know it for now.
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