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anonymous
 one year ago
Block A, with a mass of 4.0 kg, is moving with a speed of 2.0 m/s while block B, with a mass of 8.0 kg, is moving in the opposite direction with a speed of 3.0 m/s. The momentum of the center of mass of the twoblock system is:
anonymous
 one year ago
Block A, with a mass of 4.0 kg, is moving with a speed of 2.0 m/s while block B, with a mass of 8.0 kg, is moving in the opposite direction with a speed of 3.0 m/s. The momentum of the center of mass of the twoblock system is:

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IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1\(\large \vec{ \bar x} = \frac{m_1 \vec x_ 1 + m_2 \vec x_ 2}{m_1 + m_2}\) \(\large \dot{\vec{ \bar x} }= \frac{m_1 \vec {\dot x_ 1} + m_2 \vec{ \dot x_ 2} }{m_1 + m_2} = \frac{\vec p_1 + \vec p_2}{m_1 + m_2}\) \(\large \implies \vec { \bar p} = \vec p_1 + \vec p_2\) seems to make sense

anonymous
 one year ago
Best ResponseYou've already chosen the best response.012 m/s in the same direction as B?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.14(2) + 8(3) = 16

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh should it be in the same direction as B?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1dw:1439109531470:dw

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1i "think" you are multiplying the relative speed by the total mass what i tried to show in the first post is that the momentum of the CoM is actually the momentum of the system PS units of momentum?? kg m/s

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh thank you so much :)
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