anonymous
  • anonymous
Block A, with a mass of 4.0 kg, is moving with a speed of 2.0 m/s while block B, with a mass of 8.0 kg, is moving in the opposite direction with a speed of 3.0 m/s. The momentum of the center of mass of the two-block system is:
Mathematics
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anonymous
  • anonymous
Block A, with a mass of 4.0 kg, is moving with a speed of 2.0 m/s while block B, with a mass of 8.0 kg, is moving in the opposite direction with a speed of 3.0 m/s. The momentum of the center of mass of the two-block system is:
Mathematics
katieb
  • katieb
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IrishBoy123
  • IrishBoy123
\(\large \vec{ \bar x} = \frac{m_1 \vec x_ 1 + m_2 \vec x_ 2}{m_1 + m_2}\) \(\large \dot{\vec{ \bar x} }= \frac{m_1 \vec {\dot x_ 1} + m_2 \vec{ \dot x_ 2} }{m_1 + m_2} = \frac{\vec p_1 + \vec p_2}{m_1 + m_2}\) \(\large \implies \vec { \bar p} = \vec p_1 + \vec p_2\) seems to make sense
anonymous
  • anonymous
12 m/s in the same direction as B?
IrishBoy123
  • IrishBoy123
4(2) + 8(-3) = -16

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anonymous
  • anonymous
oh should it be in the same direction as B?
IrishBoy123
  • IrishBoy123
|dw:1439109531470:dw|
IrishBoy123
  • IrishBoy123
i "think" you are multiplying the relative speed by the total mass what i tried to show in the first post is that the momentum of the CoM is actually the momentum of the system PS units of momentum?? kg m/s
anonymous
  • anonymous
oh thank you so much :)

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