Find a polynomial function f(n) such that f(1), f(2), ... , f(8) is the following sequence.
4, 11, 18, 25, 32, 39, 46, 53
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
do you see any pattern in that sequence??
like if you add or subtract a particular number from the current term, you get the next term!?
Not the answer you are looking for? Search for more explanations.
suppose instead we have the sequece
3, 9, 15, 21, 27
Then I would use the function f(x)=3+6(x-1)
The reason I choose this is because we want to start at 3, and add on multiples of 6, but we want it so that 1->3, 2->9,3->15
To do that we need to be able to add multiples of 6 to 3, you might think well then we should use f(x) = 3+6x because that would add multiples of 6 to 3, but we want to get 3 when we put in 1, so we do the (x-1) to kill of that term (it goes to 0)
So we have f(x)=3+6(x-1) and sure enough f(1) = 3+6(1-1) = 3, f(2) = 3+6(2-1) = 9.....
Now do something similar with this :)