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anonymous
 one year ago
Find a polynomial function f(n) such that f(1), f(2), ... , f(8) is the following sequence.
4, 11, 18, 25, 32, 39, 46, 53
anonymous
 one year ago
Find a polynomial function f(n) such that f(1), f(2), ... , f(8) is the following sequence. 4, 11, 18, 25, 32, 39, 46, 53

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hartnn
 one year ago
Best ResponseYou've already chosen the best response.1do you see any pattern in that sequence??

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1like if you add or subtract a particular number from the current term, you get the next term!?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.032 and 46 are part of the sequence

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1suppose instead we have the sequece 3, 9, 15, 21, 27 Then I would use the function f(x)=3+6(x1) The reason I choose this is because we want to start at 3, and add on multiples of 6, but we want it so that 1>3, 2>9,3>15 To do that we need to be able to add multiples of 6 to 3, you might think well then we should use f(x) = 3+6x because that would add multiples of 6 to 3, but we want to get 3 when we put in 1, so we do the (x1) to kill of that term (it goes to 0) So we have f(x)=3+6(x1) and sure enough f(1) = 3+6(11) = 3, f(2) = 3+6(21) = 9..... Now do something similar with this :)
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