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anonymous

  • one year ago

Find a polynomial function f(n) such that f(1), f(2), ... , f(8) is the following sequence. 4, 11, 18, 25, 32, 39, 46, 53

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  1. hartnn
    • one year ago
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    do you see any pattern in that sequence??

  2. hartnn
    • one year ago
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    like if you add or subtract a particular number from the current term, you get the next term!?

  3. anonymous
    • one year ago
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    32 and 46 are part of the sequence

  4. zzr0ck3r
    • one year ago
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    suppose instead we have the sequece 3, 9, 15, 21, 27 Then I would use the function f(x)=3+6(x-1) The reason I choose this is because we want to start at 3, and add on multiples of 6, but we want it so that 1->3, 2->9,3->15 To do that we need to be able to add multiples of 6 to 3, you might think well then we should use f(x) = 3+6x because that would add multiples of 6 to 3, but we want to get 3 when we put in 1, so we do the (x-1) to kill of that term (it goes to 0) So we have f(x)=3+6(x-1) and sure enough f(1) = 3+6(1-1) = 3, f(2) = 3+6(2-1) = 9..... Now do something similar with this :)

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